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Zina [86]
3 years ago
9

Which scientist first attempted to construct a periodic table based on an element's atomic mass?

Physics
2 answers:
Nezavi [6.7K]3 years ago
7 0
That would be the Russian chemist Dmitri Mendeleev
irga5000 [103]3 years ago
6 0
Russian chemist Dmitri Mendeleev
hope this helps!!!
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Density is 1.3kg/m3 volume=? mass=? 80m 40m 15m<br>​
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From the given information, it's not possible to find the mass or the volume of the sample.

Density is their RATIO, but you can't tell if the sample is the size of an ant or a school-bus.

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Ancient peoples both feared and revered Solar and Lunar Eclipses as they happened so rarely. Explain the following about eclipse
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Answer:

Why is a solar eclipse more rare than a lunar eclispes.

Explanation:

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3 years ago
Read 2 more answers
What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit
Tresset [83]

The highest frequency sound to which the machine can be adjusted is :

  • 4179.33 Hz

<u>Given data :</u>

Pressure = 10 Pa

Speed of sound = 344 m/s

Displacement altitude = 10⁻⁶ m

<h3>Determine the highest frequency sound ( f ) </h3>

applying the formula below

Pmax = B(\frac{2\pi f}{v}) A --- ( 1 )

Therefore :

f = ( Pmax * V ) / 2\pi \beta A

 = ( 10 * 344 ) / 2\pi * 1.31 * 10⁵ * 10⁻⁶

 = 4179.33 Hz

Hence we can conclude that The highest frequency sound to which the machine can be adjusted is : 4179.33 Hz .

Learn more about Frequency : brainly.com/question/25650657

<u><em>Attached below is the missing part of the question </em></u>

<em>A loud factory machine produces sound having a displacement amplitude in air of 1.00 μm, but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maximum pressure amplitude of the sound waves is limited to 10.0 Pa. Under the conditions of this factory, the bulk modulus of air is 1.31×105 Pa. The speed of sound in air is 344 m/s. What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit?</em>

4 0
2 years ago
1) What describes the unusually large release of plasma from the sun's corona?
sergey [27]
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In fact, CME stands for "Coronal Mass Ejection", and they are huge release of plasma and magnetic field from the corona of the Sun.

2) The only statement that could be true is "<span>X and Y are both within the solar system."
In fact, the distance between X and Y is 30.2 AU (1 AU is the distance between Earth and Sun). Pluto, the farthest planet from the Sun, is located at approximately 40 AU from the Sun:  the distance between X and Y is smaller than this value, so they could be both in the solar system.</span>
4 0
4 years ago
A fillet weld has a cross-sectional area of 25.0 mm2and is 300 mm long. (a) What quantity of heat (in joules) is required to acc
HACTEHA [7]

Answer:

77362.56 J

163730.28571 J

Explanation:

A = Area = 25 mm²

l = Length = 300 mm

K = Constant = 3.33\times 10^{-6}

\eta = Heat transfer factor = 0.75

f_m = Melting factor = 0.63

T = Melting point of low carbon steel = 1760 K

Volume of the fillet would be

V=Al\\\Rightarrow V=25\times 300\\\Rightarrow V=7500\ mm^3=7500\times 10^{-9}\ m^3

The unit energy for melting is given by

U_m=KT^2\\\Rightarrow U_m=3.33\times 10^{-6}\times 1760^2\\\Rightarrow U_m=10.315008\ J/mm^3

Heat would be

Q=U_mV\\\Rightarrow Q=10.315008\times 7500\\\Rightarrow Q=77362.56\ J

Heat required to weld is 77362.56 J

Amount of heat generation is given by

Q_g=\dfrac{Q}{\eta f_m}\\\Rightarrow Q_g=\dfrac{77362.56}{0.75\times 0.63}\\\Rightarrow Q_g=163730.28571\ J

The heat generated at the welding source is 163730.28571 J

7 0
4 years ago
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