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Igoryamba
3 years ago
10

The wavelength of some violet light is 420.0 nm. what is the frequency of this violet light?

Physics
2 answers:
ipn [44]3 years ago
7 0

The frequency of light for which the wavelength is 420\,{\text{nm}}is \boxed{7.14 \times {{10}^{14}}\,{\text{Hz}}}.

Further explanation:

The frequency is a measure of number of wave’s that passes through a fixed point or place in a given time interval. The S.I unit of frequency is Hertz \left( {{\text{Hz}}} \right).

Wavelength is defined as the distance between two successive crests or troughs of a travelling wave.  

Examples of waves are sound wave, light wave, mechanical waves, surface waves etc.

Given:

The wavelength of the light used is 420\,{\text{nm}}.

The speed of the light is 3 \times {10^8}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}.

Concept:

Light is an electromagnetic wave which carries energy in the form of electric field and magnetic field. The speed of light in vacuum is 3 \times {10^8}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}.

The speed of light can be expressed in terms of wavelength of the light and the frequency of the light.

The speed of light is:

c = f \cdot \lambda

Rearrange the above expression.

\boxed{f=\frac{c}{\lambda }}                          …… (1)

Here, f is the frequency of the light, c is the speed of the light in vacuum and \lambda is the wavelength of the light.

Substitute 3 \times {10^8}\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}} for c and 420 \times {10^{ - 9}}\,{\text{m}} for \lambda in equation (1).

\begin{aligned}f&=\frac{{3\times{{10}^8}\,{{\text{m}}\mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}}{{420 \times {{10}^{-9}}\,{\text{m}}}}\\&=7.14\times {10^{14}}\,{\text{Hz}} \\ \end{aligned}

Thus, the frequency of light for which the wavelength is 420\,{\text{nm}}is \boxed{7.14 \times {{10}^{14}}\,{\text{Hz}}}.

Learn More:

1. What is the threshold frequency ν0 of cesium? Note that 1 ev (electron volt)=1.60×10−19 j. brainly.com/question/6953278

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s brainly.com/question/1979815

3. What is the frequency of light for which the wavelength is 7.1 × 102 nm brainly.com/question/9559140

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetic Waves

Keywords:

Frequency, light, wavelength, 420 nm, 4.20x10^-7 m, 7.14x10^14 Hz, vacuum, air, crests, troughs, sound wave, light wave, mechanical wave.

Sunny_sXe [5.5K]3 years ago
3 0
The equation relating wavelength and frequency of light is:
v = fλ; where v is the wave's speed, f is its frequency and λ is the wavelength.
The speed of violet light will be the same as for any elecromagnetic radiation, that is,
3 x 10⁸ m/s
3 x 10⁸ = f(420 x 10⁻⁹)
f = 7.14 x 10¹⁴ Hz
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The height of the table above the ground is 0.45 m.

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Horizontal velocity (u) = 3 m/s
  • Time (t) = 0.3 s
  • Acceleration due to gravity (g) = 10 m/s²
  • Height (h) =?

<h3>How to determine the height </h3>

The height of the table can be obtained by using the following formula:

h = ½gt²

h = ½ × 10 × 0.3²

h = 5 × 0.09

h = 0.45 m

Thus, the height of the table is 0.45 m

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5 0
2 years ago
The angular speed of the rotor in a centrifuge increases from 420 to 1420 rad/s in a time of 5.00 s. (a) Obtain the angle throug
9966 [12]

Answer:

a) θ = 2500 radians

b) α = 200 rad/s²

Explanation:

Using equations of motion,

θ = (w - w₀)t/2

θ = angle turned through = ?

w = final angular velocity = 1420 rad/s

w₀ = initial angular velocity = 420

t = time taken = 5s

θ = (1420 - 420) × 5/2 = 2500 rads

Again,

w = w₀ + αt

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6 0
3 years ago
Read 2 more answers
You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.
Andru [333]

Answer:

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Explanation:

Hi there!

The equations of height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

v = velocity of the ball at time t.

Placing the origin at the throwing point, y0 = 0.

Let´s use the equation of velocity to obtain the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.

v = v0 + g · t

6.00 m/s = 12.0 m/s -9.81 m/s² · t

(6.00 - 12.0)m/s / -9.81 m/s² = t

t = 0.612 s

Now, let´s calculate the height of the baseball at that time:

y = y0 + v0 · t + 1/2 · g · t²     (y0 = 0)

y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²

y = 5.51 m

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Have a nice day!

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