Answer:
0,93 atm
Explanation:
For this we will use PV = nRT
P is what we want to find
V = 1 L
n =
= 0,038 moles
R = 0,082 
T = 25°C = 298,15 K
P * 1 = 0,038 *0,082 * 298,15
P = 0,93 atm
Answer:
The 40g mass will be attached at 69 cm
Explanation:
First, make a sketch of the meterstick with the masses placed on it;
--------------------------------------------------------------------------
↓ Δ ↓
20 g.................50 cm.................40g
38 cm y cm
Apply principle of moment;
sum of clockwise moment = sum of anticlockwise moment
40y = 20 (38)
40y = 760
y = 760 / 40
y = 19 cm
Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm
12cm 50 cm 69cm
--------------------------------------------------------------------------
↓ Δ ↓
20 g.................50 cm.................40g
38 cm 19 cm
There’s force of friction/ drag that slows down a moving object, there’s also gravity pulling the wagon down which would help slow it down. Hope this helps good luck.
We will use the formula p = mgh
p is potential energy.
m is mass of object in kg
g is acceleration due to gravity (9.8m/s²)
h is height of the objects displacement in meters.
p = mgh → mgh = p → h = p / mg
p is 14000j, m is 40kg and g is 9.8 m/s²
h = 14000 / 40 × 9.8 → h = 1400 / 392 → h = 35.7
Therefore , the cannonball was 35.7 meters high .