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Sindrei [870]
3 years ago
15

You may have learned about the sheep clone, Dolly, in your science class. Although this experiment was greeted as a great succes

s, there are many problems with cloning. One of the ethical issues surrounding cloning has to do with the success rate of the process. This is because
A) cloning has never been and never will be possible.
B) cloning has become too successful in recent years.
C) cloning mammals has a very low success rate, and can produce severely damaged young.
D) cloning mammals has a very high success rate, and can produce severely damaged young.
Physics
1 answer:
barxatty [35]3 years ago
7 0

Answer:

C

Explanation:

Using process of elimination, A isn't right because Dolly and other animals have been cloned. B is also not correct, because there would probably not be an Issue with the success rate due to it being high. D would also not be correct for the previous reasons, and while the last bit about damaged young is correct, the first bit is worng. Hope this helps, good luck!

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A 25-kg wagon has a momentum of 300kg m/s. What is it’s acceleration?
arsen [322]

The answer is 12 ....

8 0
3 years ago
A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two parallel conducting plates separa
Zanzabum

Answer:

E=8*10^5\frac{V}{m}

Explanation:

The magnitude of the electric field between two parallel conducting plates is defined as:

E=\frac{\Delta V}{d}

Here \Delta V is the potential difference between the plates and d its separation.

The electric potential energy is defined as the product between the particle's charge and the potential difference:

U=q\Delta V

Solving for \Delta V and replacing in the electric field formula:

\Delta V=\frac{U}{q}\\E=\frac{U}{qd}

In this case we have a double charged ion, so q=2e:

E=\frac{32*10^3eV}{(2e)(2*10^{-2}m)}\\E=8*10^5\frac{V}{m}

6 0
3 years ago
Some giant ocean waves have a wavelength of 25 m and a frequency of
kolezko [41]

Answer:

Explanation:

The frequency equation for waves is

f=\frac{v}{\lambda} where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:

.26=\frac{v}{25} so

v = .26(25) and

v = 6.5 meters/second

3 0
3 years ago
How to solve this step by step
victus00 [196]
Well, it goes 60 miles in one hour......so set up a ratio.....
60 miles/5 miles = 1 hr/x.....you'll get 60x = 5....then 5/60 would be 0.083 

7 0
3 years ago
A projectile is launched from ground level with an initial speed of 47 m/s at an angle of 0.6 radians above the horizontal. It s
Zarrin [17]

Answer:

30.67m

Explanation:

Using one of the equations of motion as follows, we can describe the path of the projectile in its horizontal or vertical displacement;

s = ut ± \frac{1}{2} at^2               ------------(i)

Where;

s = horizontal/vertical displacement

u = initial horizontal/vertical component of the velocity

a = acceleration of the projectile

t = time taken for the projectile to reach a certain horizontal or vertical position.

Since the question requires that we find the vertical distance from where the projectile was launched to where it hit the target, equation (i) can be made more specific as follows;

h = vt ± \frac{1}{2} at^2               ------------(ii)

Where;

h = vertical displacement

v = initial vertical component of the velocity = usinθ

a = acceleration due to gravity (since vertical motion is considered)

t = time taken for the projectile to hit the target

<em>From the question;</em>

u = 47m/s, θ = 0.6rads

=> usinθ = 47 sin 0.6

=> usinθ = 47 x 0.5646 = 26.54m/s

t = 1.7s

Take a = -g = -10.0m/s   (since motion is upwards against gravity)

Substitute these values into equation (ii) as follows;

h = vt - \frac{1}{2} at^2

h = 26.54(1.7) - \frac{1}{2} (10)(1.7)^2

h = 45.118 - 14.45

h = 30.67m

Therefore, the vertical distance is 30.67m        

7 0
4 years ago
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