Answer:
a,b) #_ {electron} = 1.64 10¹⁹ electrons, c) R = 19.54 Ω, d) V = 10.3 V
Explanation:
a and b) The current is defined as the number of electrons that pass per unit of time
let's look for the load
Q = I t
Q = 0.526 5
Q = 2.63 C
Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?
#_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)
#_ {electron} = 1.64 10¹⁹ electrons
c) the resistance of a wire is given by
R = ρ l / A
where the resistivity of tungsten is 5.6 10⁻⁸ Ω
the area of the wire is
A = π r2 = π d²/4
we substitute
R = 
let's calculate
R = 5.6 10⁻⁸ 0.580 
R = 19.54 Ω
d) let's use ohm's law
V = i R
V = 0.526 19.54
V = 10.3 V
This is problem of free falling
objects, which can be solved using the formula:
V = sqrt(2gy)
Where v is the velocity upon
impact
G is the acceleration due to
gravity ( 9.81 m/s2)
Y is the height
Since Venessa is 3.5 m
Y = 30 -3.5 = 26.5 m
V = sqrt(2 (9.81 m/s2) ( 26.5
m))
<span>V = 22.8 m/s</span>
The answer is a property of density. The higher the density, the higher the pressure at the bottom.
Pressure = mass / Area. So given that the 4 samples occupy the same area at the bottom, the mass is going to be the determining factor. Per given volume, mercury has the largest mass. The answer is A
The distance between Mars and the Sun in the scale model would be 1140 m
Explanation:
In this scale model, we have:
represents an actual distance of
The actual distance between Mars and the Sun is 228 million km, therefore
On the scale model, this would corresponds to a distance of 
.
Therefore, we can write the following proportion:
And solving for , we find:
Learn more about distance:
brainly.com/question/3969582
#LearnwithBrainly
Answer:
a = 1 m/s² and
Explanation:
The first two parts can be seen in attachment
We use Newton's second law on each axis
Y axis
Ty - W = 0
Ty = w
X axis
Tx = m a
With trigonometry we find the components of tension
Sin θ = Ty / T
Ty = T sin θ
Cos θ = Tx / T
Tx = T cos θ
We calculate the acceleration with kinematics
Vf = Vo + a t
a = (Vf -Vo) / t
a = (20 -10) / 10
a = 1 m/s²
We substitute in Newton's equations
T Sin θ = mg
T cos θ = ma
We divide the two equations
Tan θ = g / a
θ = tan⁻¹ (g / a)
θ = tan⁻¹ (9.8 / 1)
θ = 84º
We see that in the expression of the angle the mass does not appear therefore you should not change the angle
