Well I don't know !
Let's work it out.
The gravitational force between two objects is
F = G · M₁·M₂ / R² .
'G' is the 'universal gravitational constant'. We could look it up.
'M₁' is the mass of one object
'M₂' is the mass of the other object
'R' is the distance between their centers.
It looks complicated, but stay with me. We can do this !
We know all the numbers, so we can calculate the force.
'G' is 6.67 x 10⁻¹¹ newton·meter² / kg² (I looked it up. You're welcome.)
'M₁' is 15 kg
'M₂' is 15 kg
'R' is 0.25 meter.
Now it's time to pluggum in.
F = G · M₁·M₂ / R²
= (6.67 x 10⁻¹¹ newton·meter² / kg²) · (15 kg) · (15 kg) / (0.25 m²)
= (6.67 x 10⁻¹¹ · 15 · 15 / 0.0625) N·m²·kg·kg / kg²·m²
= 2.4 x 10⁻⁷ Newton .
That a force equivalent to about 0.00000086 of an ounce.
This is the answer to part-a.
Concerning the answer to part-b ...
Personally, I could not detect this force, no matter what kind of equipment
I had. But I am just a poor schlepper engineer, educated in the last Century,
living out my days on Brainly and getting my kicks from YouTube videos.
I am not pushing the box to the envelope, or thinking outside the cutting
edge ... whatever.
I am sure there are people ... I can't name them, because they keep a
low profile, they stay under the radar, they don't attract a lot of media
attention, their work is not as newsworthy as the Kardashians, and plus,
they seldom call me or write to me ... but I know in my bones that there
are people who have measured the speed of light to NINE significant figures,
aimed a spacecraft accurately enough to take close-up pix of Pluto ten years
later, and detected gravity waves from massive blobs that merged 13 billion
years ago, and I tell you that YES ! THESE guys could detect and measure
a force of 0.86 micro-ounce if they felt like it !
Answer:
The total work that the rope does to Mangnus is - 5780 Jules.
Explanation:
By definition, the work is defined as:
Where F and d are the force and the total displacement. Note that in the definition the product is a scalar product since F and d are both vectors.
Take into account that according to third Newton's law the force that the rope does to Magnus is opposite to the force that Magnus does to the rope, therefore the scalar product will be negative due the rope's force goes against to Magnus displacement.
For calculating the work, we take 2500 N as the value for the force and 2.312 meters as the value for the displacement:
Answer:a force of attraction exerted by each particle of matter in the universe on every other particle
Explanation:gravitation describes the attractive force between any two masses
The normal force acting on April as she stands on a flat surface is 705.6 N.
Normal force of the girl
Fₙ = mg
where;
- Fₙ is the normal force of the girl
- m is mass of the girl
- g is acceleration due to gravity
Fₙ = 72 x 9.8
Fₙ = 705.6 N
Thus, the normal force acting on April as she stands on a flat surface is 705.6 N.
Learn more about normal force here: brainly.com/question/14486416
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your answer is the letter (b)
