Answer:
<em> The planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>
Explanation:
Acceleration: This can be defined as the rate of change of velocity. The S.I Unit of acceleration is m/s². Acceleration is a vector quantity because it can be represented both in magnitude and in direction.
Acceleration can be represented mathematically as
a = v/t.................................... Equation 1
Where a = acceleration, v = velocity, t= time.
<em>Given: v = 115 m/s, t = 13.0 s</em>
<em>Substituting these values into equation 1</em>
<em>a = 115/13</em>
<em>a = 8.846 m/s² moving east</em>
<em>Thus the planes average acceleration in magnitude and direction = 8.846 m/s² moving east</em>
Answer:
101.54m/h
Explanation:
Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;
Let l be the be the distance further away at which they will meet from the current points;
#The speed toward each other.

Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h
Answer:
Since the area of the perfect square is 11650, and all of a squares sides ar equal, we just need to find the square root.
The square root of 11650 is 107.935166.
One side of the square is 107.935166
107.935166 x 107.935166 = 11650
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Answer:
diameter of largest orbit is 0.60 m
Explanation:
given data
isotopes accelerates KE = 6.5 MeV
magnetic field B = 1.2 T
to find out
diameter
solution
first we find velocity from kinetic energy equation
KE = 1/2 × m×v² ........1
6.5 × 1.6 ×
= 1/2 × 1.672 ×
×v²
v = 3.5 ×
m/s
so
radius will be
radius =
........2
radius =
radius = 0.30
so diameter = 2 × 0.30
so diameter of largest orbit is 0.60 m
Answers:
a) 
b) 
c) 
Explanation:
<h3>a) Impulse delivered to the ball</h3>
According to the Impulse-Momentum theorem we have the following:
(1)
Where:
is the impulse
is the change in momentum
is the final momentum of the ball with mass
and final velocity (to the right) 
is the initial momentum of the ball with initial velocity (to the left) 
So:
(2)
(3)
(4)
(5)
<h3>b) Time </h3>
This time can be calculated by the following equations, taking into account the ball undergoes a maximum compression of approximately
:
(6)
(7)
Where:
is the acceleration
is the length the ball was compressed
is the time
Finding
from (7):
(8)
(9)
(10)
Substituting (10) in (6):
(11)
Finding
:
(12)
<h3>c) Force applied to the ball by the bat </h3>
According to Newton's second law of motion, the force
is proportional to the variation of momentum
in time
:
(13)
(14)
Finally:
