Ask question

Ask question

All categories

3 years ago

15

When did Ptolemy live?

1 answer:

Gelneren [198K]3 years ago

7 0

100 AD<<<<<<<<<<<<<<<<<<<<<<<<

You might be interested in

A 3.00 kg stone is dropped from a 39.2 m high building. when the stone has fallen 19.6 m, the magnitude of the impulse the earth

tatiyna

<span>The formulas are, Impulse = mv-mu ....... (1) v^2 = u^2 + 2as .......... (2) We know that, u=0 a=acceleration=gravity = 9.80665 m/s^2 = 9.81 m/s^2 s=19.6 sub (2) we get, v^2 = 0+ 2*9.81*19.6 v^2 = 2*9.81*19.6 v^2 = 384.552 v = 19.6099 v = 19.61 m/s Sub v=19.61 m/s in (1) we get, Impulse = mv - mu we know that u=0; v= 19.61 m/s; m= 3.00 kg Impulse = 3(19.61) - 3(0) Impulse = 58.83-0 Impulse = 58.83 Ns. Therefore the gravitational force exerted by the stone is 58.83 Ns.</span>

4 0

4 years ago

A push or a pull is called _____. User: The metric unit of force is the _____.

Ahat [919]

Force
Newton, abbreviated as N

7 0

3 years ago

A worker pushes a 1080 N crate with a horizontal force of 345 N a distance of 14 m. Assume the coefficient of kinetic frictin be

amm1812

Answer:

The work done by the worker on the crate is 4830 J.

Explanation:

Given that,

Force = 1080 N

Horizontal force = 345 N

Distance d = 14 m

Coefficient of friction = 0.22

We need to calculate the work done

Using formula of work done

$W = Fd$

F = force

d = distance

Put the value into the formula

$W=345\times14$

$W=4830\ J$

Hence, The work done by the worker on the crate is 4830 J.

3 0

3 years ago

Read 2 more answers

The motion of as car is drawn is vi against th graph

LenKa [72]

10 and 40 would be your answer i believe.

3 0

3 years ago

A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a

aleksklad [387]

Answer:

$V=9.2565m/s$

Explanation:

From the question we are told that:

Force $F = 34 N$

Time $t = 0.6 s$

Length of pedal $l_p=16.5cm \approx0.165m$

Radius of wheel $r = 33 cm = 0.33 m$

Moment of inertia, $I = 1200 kgcm2 = 0.12 kg.m2$

Generally the equation for Torque on pedal $\mu$ is mathematically given by

$\mu=F*L\\\mu=34*0.165$

$\mu=5.61N.m$

Generally the equation for angular acceleration $\alpha$ is mathematically given by

$\alpha=\frac{\mu}{l}$

$\alpha=\frac{5.61}{0.12}$

$\alpha=46.75$

Therefore Angular speed is \omega

$\omega=\alpha*t$

$\omega=(46.75)*(0.6)$

$\omega=28.05rad/s$

Generally the equation for Tangential velocity V is mathematically given by

$V=r\omega$

$V=(0.33)(28.05)$

$V=9.2565m/s$

5 0

3 years ago