<span>The formulas are,
Impulse = mv-mu ....... (1)
v^2 = u^2 + 2as .......... (2)
We know that,
u=0
a=acceleration=gravity = 9.80665 m/s^2 = 9.81 m/s^2
s=19.6
sub (2) we get,
v^2 = 0+ 2*9.81*19.6
v^2 = 2*9.81*19.6
v^2 = 384.552
v = 19.6099
v = 19.61 m/s
Sub v=19.61 m/s in (1) we get,
Impulse = mv - mu
we know that u=0; v= 19.61 m/s; m= 3.00 kg
Impulse = 3(19.61) - 3(0)
Impulse = 58.83-0
Impulse = 58.83 Ns.
Therefore the gravitational force exerted by the stone is 58.83 Ns.</span>
Force
Newton, abbreviated as N
Answer:
The work done by the worker on the crate is 4830 J.
Explanation:
Given that,
Force = 1080 N
Horizontal force = 345 N
Distance d = 14 m
Coefficient of friction = 0.22
We need to calculate the work done
Using formula of work done

F = force
d = distance
Put the value into the formula


Hence, The work done by the worker on the crate is 4830 J.
10 and 40 would be your answer i believe.
Answer:

Explanation:
From the question we are told that:
Force
Time 
Length of pedal 
Radius of wheel 
Moment of inertia, 
Generally the equation for Torque on pedal
is mathematically given by


Generally the equation for angular acceleration
is mathematically given by



Therefore Angular speed is \omega



Generally the equation for Tangential velocity V is mathematically given by


