Answer:
14.9 m /s
Explanation:
n = n° x v /[ v -v (s) ]
n is apparent frequency , n° is source frequency,v is speed of sound and v(s)
speed of source.
2300 = 2200 x 343 / [343 -v(s)]
v (s ) = 14.9 m /s.
Energy remains constant is the answer you are looking for but it only applies, when no outside forces act on the object.
Ans: a = 2.50 m/s^2
Explanation:
First convert the mass in its standard unit i.e. kilogram(kg):
2250 lbs = 1020.583kg
Next use Newton's Second law:
F = ma
Where F = 2552N
m = 1020.583kg
=> a = (2552/1020.583)
a = 2.50 m/s^2
A positively charged particle in an atom's nucleus is called "an proton".
Use this kinematics equation to the describe the vertical motion of the ball as a function of time:
H(t) = X + Vt + 0.5At²
H(t) is the height of the ball
X is the initial height of the ball
V is the initial vertical velocity of the ball
A is the vertical acceleration of the ball
Given values:
X = 100m
V = -2m/s
A = -9.81m/s² (constant acceleration due to gravity near the surface of the earth)
Plug in the values:
H(t) = 100 - 2t - 4.905t²
To find a time t for when the ball hits the ground, plug in H(t) = 0 and solve for t:
100 - 2t - 4.905t²
t = 4.316s, -4.724s
Reject the negative value because this doesn't make sense in the context of the question.
t = 4.316s
For the ball's horizontal motion under constant velocity:
X = VΔt
X is the horizontal distance traveled by the ball
V is the ball's velocity
Δt is the elapsed time
Given values:
V = 2.0m/s
Δt = 4.316s (from previous work)
Plug in and solve for X:
X = 2.0×4.316
X = 8.632m
The girl will find the ball 8.632m from where her hot air balloon will land.