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Ann [662]
3 years ago
15

Select the correct answer. A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meter

s over the first 10 seconds of its travel. What is its average speed during the time from t = 5 seconds to t = 10 seconds? A. 2 meters/second B. 3 meters/second C. 4 meters/second D. 5 meters/second E. 6 meters/second
Physics
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

2 m/s

Explanation:

...........................

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The pressure in a compressed air storage tank is 1200 kPa. What is the tank’s pressure in (a) kN and m units; (b) kg, m, and s u
elixir [45]

Explanation:

Given data

Pressure P=1200 kPa

To find

Pressure in

(a) kN/m²

(b) kg/m.s²

(c) kg/km.s²

Solution

For Part (a)

P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )\\P=1200kN/m^{2}

For Part (b)

P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )(\frac{1000kg.m/s^{2} }{1kN} )\\P=1,200,000kg/m.s^{2}

For Part (c)

P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )(\frac{1000kg.m/s^{2} }{1kN} )(\frac{100m}{1km} )\\P=1,200,000,000kg/km.s^{2}

8 0
4 years ago
A car is moving in uniform circular motion. If the car's speed were to double to keep the car moving with the same radius, the a
Anestetic [448]

Answer:

Increase by a factor of 4.

Explanation:

The acceleration of a car moving with speed v in a circle of radius R is given by:

a=\frac{v^2}{R}.

Now if we double the speed v in the equation above, it becomes 2v. Thus:

a=\frac{v^2}{R}\:\: {\rightarrow}\:\: a_n=\frac{(2v)^2}{R}=4\frac{v^2}{R}=4a.

Therefore the acceleration is increased by a factor of 4.

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3 years ago
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