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san4es73 [151]
3 years ago
12

A student wishes to investigate how the material of which an object is made affects how the object changes temperature. The stud

ent will heat objects to a temperature of 50C, then see how long it takes the objects to cool down to room temperature. For this investigation, it is most important that the student use objects that–are the same size, but made of different materials.will not melt at temperatures about 100C.release thermal energy quickly to the environment.are made of metals, since they conduct heat.
Physics
1 answer:
Sati [7]3 years ago
3 0

Answer:

Objects that are of the same size but made of different materials

Explanation:

The rate it takes the object to cool is equivalent to the rate of heat loss

The rate of heat loss is given by the equation:

dQ/dt = K(T-T₀)

Where T = Temperature of the hot surface

T₀ = Temperature of the surrounding

K = constant

Both K and the rate of heat loss depends on the:

  • nature of the surface
  • Area of the surface
  • Material of the surface of the body

Since the student only wants to know how the material in which the object is made of affects change in temperature, it means only the materials must be varied while other factors such as area and the size of the objects are kept constant.

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andrew11 [14]

The apple is lifted by 1.1 m

<u>Explanation</u>:

  • Given that, mgh = 2 J and mass of apple = 180g
  • Step 1: convert grams to kg as work is given in SI units.

                    180 g = 0.18 kg

  • Step 2: substitute in the formula for work done.

                    0.18 * 10 * h = 2

  • Step 3: calculate the value of h from this formula.

                      h = 2/1.8

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Evgesh-ka [11]

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200 , 0 , 133.33333

Explanation:

velocity = change of X / change of T

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3 years ago
If 50 km thick crust having an average density of 3.0 g/cm3 has a surface elevation of 2.5 km above sea level, what would you pr
RUDIKE [14]

Answer:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

Thus let the density of the material be Pm

50*3= 47.5*Pm

Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube

Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

Explanation:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

Thus let the density of the material be Pm

50*3= 47.5*Pm

Therefore: Pm= (50*3)/47.5= 3.16gram per centimeter cube

Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

5 0
3 years ago
If are spaced closely together on the map,there is a drastic temperature change over the distance
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If <em>the isotherms</em> are spaced closely together over some portion of the map, there is a drastic temperature change over that portion.

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