The answer would be:
D.
Here's why:
According to the Law of Reflection, in a smooth the angle of incidence should be equal to the angle of reflection. This means that the angle of incidence of the ray from the normal, will create a reflected ray that measures the same as ray of incidence from the normal.
It is confusing, but look that the image below to grasp the explanation.
We are given the coefficient of friction which is:
Cf = 0.90
The acceleration based on this would be:
a = -Cf * g
a = -0.90 * (9.81 m/s^2)
a = -8.83 m/s^2
Calculate the distance at his total stop v = 0 using the formula:
v^2 = vo^2 + 2ad
where v is final velocity = 0, vo is initial velocity = 16, d is distance
0 = 16^2 + 2 (-8.83) d
d = 14.5 m
So he is short by 0.5 m, he does not reach the finish line
Data:
a) v = 84 m/s
r = 225 m
Ac =?
b) Ac = 9.8 m/s^2
v = ?
Formula: Ac = v^2 / r
Solution
a) Ac = (84 m/s)^2 / (225 m) = 31.36 m/s^2
To measure it in terms of g, divide by g = 9.8 m/s^2
=> Ac = 31.36 m/s^2 / [ 9.8 m/s^2 / g] = 3.2 g
Answer: Ac = 3.2 g
b) Ac = 9.8 m/s^2
v^2 = Ac * r = 9.8 m/s^2 * 225 m = 2,205 m^2 / s^2
=. v = 46.96 m/s ≈ 47 m/s
Answer: 47 m/s
Answer:
Ok so I think i got it, Left is negative and so is down so if its facing down or left its negative force but if its right and up its positive so
A is neg
B is pos
C is Pos
D is Neg
E is Neg
f is Neg
Explanation:
hope that helps and have a great day
if it helps think about giving a good rating and branniest answer
Answer:
16 times.
Explanation:
The rate of the radiation dose is , R = 200 ×10^{-3} rad/hr
Time consumed, t = 40 hr
The magnitude of Q.F for the neutrons, Q.F = 2
Thus the effective radiation dose is:
Thus, the effective dose allowable yearly = 16 times