Answer:
v = 5.9 x 10⁷ m/s
Explanation:
The kinetic energy of the electron in terms of potential difference is given as:
--------------- equation (1)
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = Potential Difference = 9.9 KV = 9900 Volts
The kinetic energy in general is given as:
--------- equation (2)
where,
m = mass of electron = 9.1 x 10⁻³¹ kg
v = speed of electron = ?
Therefore, comparing equation (1) and equation (2), we get:
<u>v = 5.9 x 10⁷ m/s</u>
The number of protons an element has is its atomic number so the atomic number would be 29
Answer:
puck decelerates due to the kinetic frictional force μk mg
Explanation:
given data
total distance = 12 m
coefficient of kinetic friction = 0.28
solution
we will apply equation of motion that is
v² - u² = 2 × a × s ................1
we know acceleration will be
a =
Then we have
Force = mass × acceleration .................2
m × = -μk mg
The puck decelerates due to the kinetic frictional force μk mg
and frictional force is negative as it opposes the motion.
so we get initial velocity of the puck which is strike.
To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.
The force can be described as
Where,
m = Mass
g = Gravitational acceleration
At the same time the Density can be defined as
Where,
m = mass
V = Volume
Replacing the value of the mass at the equation of Force we have,
Since the difference between the two forces gives us the total Force then we have to
Where
Force of the water
= Force of plastic
Therefore with the values for this force we have,
Therefore the tension in the thread is 16.412N
Answer:
A) yes
Explanation:
First section of trip: 30 miles in 40 minutes
Second section of trip: 15 miles in 20 minutes
The formula for speed is distance over time
Calculate the speeds for each section of the trip.
First:
k = d/t
k = 30miles/40minutes <= reduce fraction by 10 (30÷10 and 40÷10)
k = 3 miles / 4 minutes
Second:
k = d/t
k = 15miles/20minutes <= reduce fraction by 5 (15÷5 and 20÷5)
k = 3 miles / 4 minutes
Therefore there is a constant speed because both sections of the trip are driving at "3 miles / 4 minutes".
3 miles / 4 minutes can be also formatted as:
0.75 miles per minute.