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Dahasolnce [82]
3 years ago
7

Both segments of the wire are made of the same metal. Current I1 flows into segment 1 from the left. How does current I1 in segm

ent 1 compare to current 12 in segment 27 A) h 12 B) l12 C) licl D) Not enough information is provided
Physics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

current I1 = current I2

Explanation:

since the wire is made up of the same material, from Kirchoff's current law sum of currents entering a particular node or segment of wire is equals to the sum of currents leaving that particular node or segment of wire

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2 Calculate the mass of a car that hits a wall, during an accident, with a force of 961 N and an acceleration of 31m/s2. (4D) (F
Pachacha [2.7K]

Answer: 31kg

Explanation:

(F=mxa)

Rearranged

M=f÷a

961÷31=31

8 0
3 years ago
Explain which planets have seasons and why some planets have none at all.
Sergeu [11.5K]

Answer:

Some planets have seasons some don't bc of the distance from the sun some of them are too cold or too hot to have seasons

8 0
3 years ago
A 0.0780 kg lemming runs off a
kotegsom [21]

Answer:

5.01 J

Explanation:

Info given:

mass (m) = 0.0780kg

height (h) = 5.36m

velocity (v) = 4.84 m/s

gravity (g) = 9.81m/s^2

1. First, solve for Kinetic energy (KE)

KE = 1/2mv^2

1/2(0.0780kg)(4.84m/s)^2 = 0.91 J

so KE = 0.91 J

2. Next, solve for Potential energy (PE)

PE = mgh

(0.0780kg)(9.81m/s^2)(5.36m) = 4.10 J

so PE = 4.10 J

3. Mechanical Energy , E = KE + PE

Plug in values for KE and PE

KE + PE = 0.91J + 4.10 J = 5.01 J

4 0
3 years ago
light of a certain frequency has a wavelength of 438 nm in water.What is the wavelength of this light in benzene​
sveticcg [70]

Answer:

388.97 nm

Explanation:

The computation of the wavelength of this light in benzene is shown below:

As we know that

n (water) = 1.333

n (benzene) = 1.501

\lambda (water) \times n(water) = \lambda (benzene) \times n(benzene)

And, the wavelength of water is 438 nm

\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}]

Now placing these values to the above formula

So,

= 438 \times \frac{1.333}{1.501}

= 388.97 nm

We simply applied the above formula so that we can easily determine the wavelength of this light in benzene​ could come

5 0
3 years ago
What atmospheric conditions can cause sound wave refractions similar to those observed in the ocean?
Romashka-Z-Leto [24]
It has to do with we're the water is coming from and we're it's at like city or town
4 0
3 years ago
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