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Vsevolod [243]
3 years ago
15

A box is being moved with a velocity v by a force p (parallel to v) along a level horizontal floor. The normal force is FN, the

kinetic firictional force is fk, and the weight of the box is mg. Decide which forces do positive, zero, or megative work. Provide a reason for each of your answers
Physics
1 answer:
Andrej [43]3 years ago
6 0
La neta no se no hablo inglés
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Pluto's orbit brings it inside the orbit of _____.<br><br> Neptune<br> Saturn<br> Venus<br> Uranus
Margarita [4]

Answer:

Pluto's orbit brings it inside the orbit of <u>Neptune</u>.

6 0
4 years ago
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A dragster completed a 402.3-(0.2500-mi) run in 5.023s. If the car had a constant acceleration, what was its acceleration and fi
Ray Of Light [21]

Answer:

v = 80.092 m/s

a = 15.945 m/s²

Explanation:

Given,

The distance completed by the dragster, d = 402.3 m

The time taken by the dragster to complete that distance is, t = 5.023 s

The initial velocity of the dragster, u = 0

The final velocity of the dragster, v = ?

The acceleration of the dragster, a = ?

The velocity of the body is given by the formula

                                  v = d/t  m/s

Substituting the above values inn the equation

                                  v = 402.3 m / 5.023 s

                                     = 80.092 m/s

So, the velocity of the dragster is, v = 80.092 m/s

The acceleration of the body is given by the formula

                                   a = (v - u)/t  m/s²

Substituting the above values in the equation

                                      = (80.092 - 0) / 5.023

                                      = 15.945 m/s²

Hence, the acceleration of the dragster is, a = 15.945 m/s²

6 0
3 years ago
This is a net gain or loss of electrons. *
krok68 [10]
A net gain of electrons.
8 0
3 years ago
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What would make oppositely charged objects attract each other more? increasing the positive charge of the positively charged obj
kykrilka [37]

Answer:

A.

Explanation:

I did the test :D

3 0
3 years ago
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Suppose that you have been chosen for a space mission to a distant planet. Due to the length of time you'll be away from Earth y
Contact [7]

Answer:

I should be active for 15 hours to meet the physical activity requirement.

Explanation:

Since time dilates in moving objects, we use the formula t = t₀/√(1 - β²) where t = time in space vehicle, t₀ = time on earth = 9 hours and β = v/c where v = speed of space vehicle = 0.8c.

So, t = t₀/√(1 - β²)

t = 9/√(1 - (v/c)²)

= 9/√(1 - (0.8c/c)²)

= 9/√(1 - (0.8)²)

= 9/√(1 - (0.64)

= 9/√0.36

= 9/0.6

= 15 hr

So, according to a timer on the space vehicle, I should be active for 15 hours to meet the physical activity requirement.

8 0
4 years ago
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