Answer:
21.7 m/s
Explanation:
To solve this problem, we have to write the equations of motion along the two directions: horizontal and vertical.
Horizontal direction:
![N sin \theta + \mu N cos \theta = m\frac{v^2}{r}](https://tex.z-dn.net/?f=N%20sin%20%5Ctheta%20%2B%20%5Cmu%20N%20cos%20%5Ctheta%20%3D%20m%5Cfrac%7Bv%5E2%7D%7Br%7D)
Vertical direction:
![N cos \theta - \mu N sin \theta - mg = 0](https://tex.z-dn.net/?f=N%20cos%20%5Ctheta%20-%20%5Cmu%20N%20sin%20%5Ctheta%20-%20mg%20%3D%200)
where:
N is the normal reaction on the car
is the banking angle of the road
is the coefficient of friction of concrete
m is the mass of the car
v is the speed of the car
r = 40 m is the radius of the curve
is the acceleration due to gravity
Combining the two equations together, we can find the maximum speed allowed for the car:
![v=\sqrt{\frac{rg(sin \theta + \mu cos \theta)}{cos \theta - \mu sin \theta}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7Brg%28sin%20%5Ctheta%20%2B%20%5Cmu%20cos%20%5Ctheta%29%7D%7Bcos%20%5Ctheta%20-%20%5Cmu%20sin%20%5Ctheta%7D%7D)
And substituting the data we have, we find:
![v=\sqrt{\frac{(40)(9.8)(sin 20^{\circ} + (0.58) cos 20^{\circ} )}{cos 20^{\circ} - (0.58) sin 20^{\circ} }}=21.7 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B%2840%29%289.8%29%28sin%2020%5E%7B%5Ccirc%7D%20%2B%20%280.58%29%20cos%2020%5E%7B%5Ccirc%7D%20%29%7D%7Bcos%2020%5E%7B%5Ccirc%7D%20%20-%20%280.58%29%20sin%2020%5E%7B%5Ccirc%7D%20%7D%7D%3D21.7%20m%2Fs)
Explanation:
Solids have a definite shape and definite volume.
It depends, one can be darker or lighter. There can be many colors of shade, there can also be different patterns of shade.
You answer should be C sorry if I’m wrong
Answer:
1.5 m/s^2
Explanation:
Force = 3000 Newtons
Mass = 2000 kilograms
Force = Mass x Acceleration
This rearranged to:
Acceleration = Force / Mass
Acceleration = 3000 / 2000 = 1.5 m/s^2