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nirvana33 [79]
2 years ago
8

What do scientists use to determine the temperature of a star? A. thermometer B. distance from Earth C. composition D. color

Physics
2 answers:
AysviL [449]2 years ago
5 0

The answer is D. Color !

babymother [125]2 years ago
3 0

Answer:

D. color

because its relevant

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We cannot see a new moon in our sky because ________. We cannot see a new moon in our sky because ________. a new moon is quite
olasank [31]

Answer:

a new moon is quite near the Sun in the sky

Explanation:

7 0
3 years ago
How can you use distance and displacement to describe an object's motion​
andrew11 [14]

Answer:

distance can describe the total distance moved and displacement shows how far something has moved from its starting position (in a straight line from point a to point b) the object doesn't have to move in a straight line, but that is how displacement is measured

8 0
2 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
2 years ago
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