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Rufina [12.5K]
4 years ago
7

Plz help :(

Chemistry
1 answer:
ziro4ka [17]4 years ago
5 0
<h2>Answer:0.5 moles,1 mole</h2>

Explanation:

Sr(NO_{3})_{2} is readily soluble in water.

Sr(NO_{3})_{2} dissolves in water to give Sr^{2+} ions and NO_{3}^{-} ions.

The reaction is

Sr(NO_{3})_{2}→Sr^{2+}+2NO_{3}^{-}

So,1 mole of Sr(NO_{3})_{2} gives 1 mole of Sr^{2+} and 2 moles of NO_{3}^{-}.

So,0.5 moles of Sr(NO_{3})_{2} gives 0.5 moles of Sr^{2+} and 1 mole of NO_{3}^{-}.

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In which of the following reactions will Kc = Kp? a. 4 NH3(g) + 3 O2(g) ⇌ 2 N2(g) + 6 H2O(g) b. SO3(g) + NO(g) ⇌ SO2(g) + NO2(g)
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Answer:

The correct option is <em>b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)</em>

Explanation:

The relation between Kc and Kp is given by the following equation:

Kp = Kc (RT)^{dn}

where R is the gas constant (0,082 L.atm/K.mol), T is the temperature (in K) and dn is the change in moles.

The change in moles (dn) is calculated as:

dn = moles of products - moles reactants

If dn=0, RT= 1 ⇒ Kc=Kp

We calculate dn for each reaction from the estequiometrial coefficients of products and reactants as follows:

a) 4 NH₃(g) + 3 O₂(g) ⇌ 2 N₂(g) + 6 H₂O(g)

dn= (2+6) - (4+3) = 1 ⇒ Kc ≠ Kp

b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

dn = (1+1) - (1+1)= 0 ⇒ Kc = Kp

c) 2 N₂(g) + O₂(g) ⇌ 2 N₂O(g)

dn= 2 - (2+1) = -1 ⇒ Kc ≠ Kp

d) 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

dn = 2 - (2+1) = -1 ⇒ Kc ≠ Kp

The reaction in which Kc=Kp is b), because reactants and products have the same number of moles.

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