Which muscles does the brain control

In an internal combustion engine, octane reacts with oxygen gas to produce carbon dioxide and water and a large amount of energy

sergij07 [2.7K]

Answer:

When octane and oxygen gas are burned in our cars, carbon dioxide and water come out of the exhaust. The increase in carbon dioxide in the atmosphere is causing global warming. 4.

Explanation:

5 0

2 years ago

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A 25.0 g sample of metal at

Nadya [2.5K]

The change in temperature of the metal is 6.1°C. Details about change in temperature can be found below.

<h3>How to calculate change in temperature?</h3>

The change in temperature of a substance can be calculated by subtracting the initial temperature of the substance from the final temperature.

According to this question, a 25.0 g sample of metal at 16.0 °C is warmed to 22.1 °C by 259J of energy.

This means that the change in temperature of the metal can be calculated as:

∆T = 22.1°C - 16°C

∆T = 6.1°C

Therefore, the change in temperature of the metal is 6.1°C.

Learn more about change in temperature at: brainly.com/question/19051558

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7 0

1 year ago

Calculate E ° for the half‑reaction, AgCl ( s ) + e − − ⇀ ↽ − Ag ( s ) + Cl − ( aq ) given that the solubility product constant

antoniya [11.8K]

Answer: The value of $E^{o}$ for the half-cell reaction is 0.222 V.

Explanation:

Equation for solubility equilibrium is as follows.

$AgCl(s) \rightleftharpoons Ag^{+}(aq) + Cl^{-}(aq)$

Its solubility product will be as follows.

$K_{sp} = [Ag^{+}][Cl^{-}]$

Cell reaction for this equation is as follows.

$Ag(s)| AgCl(s)|Cl^{-}(0.1 M)|| Ag^{+}(1.0 M)| Ag(s)$

Reduction half-reaction: $Ag^{+} + 1e^{-} \rightarrow Ag(s)$ , $E^{o}_{Ag^{+}/Ag} = 0.799 V$

Oxidation half-reaction: $Ag(s) + Cl^{-}(aq) \rightarrow AgCl(s) + 1e^{-}$ , $E^{o}_{AgCl/Ag}$ = ?

Cell reaction: $Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)$

So, for this cell reaction the number of moles of electrons transferred are n = 1.

Solubility product, $K_{sp} = [Ag^{+}][Cl^{-}]$

= $1.77 \times 10^{-10}$

Therefore, according to the Nernst equation

$E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}$

At equilibrium, $E_{cell}$ = 0.00 V

Putting the given values into the above formula as follows.

$E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}$

$0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}$

$E^{o}_{cell} = \frac{0.0592}{1} log \frac{1}{K_{sp}}$

= $0.0591 V \times log \frac{1}{1.77 \times 10^{-10}}$

= 0.577 V

Hence, we will calculate the standard cell potential as follows.

$E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}$

$0.577 V = E^{o}_{Ag^{+}/Ag} - E^{o}_{AgCl/Ag}$

$0.577 V = 0.799 V - E^{o}_{AgCl/Ag}$

$E^{o}_{AgCl/Ag}$ = 0.222 V

Thus, we can conclude that value of $E^{o}$ for the half-cell reaction is 0.222 V.

3 0

2 years ago

2. Solid sodium reacts with gaseous chlorine to produce sodium chloride.

stich3 [128]

2Na (s) + Cl2 (g) = 2NaCl (s)

8 0

2 years ago

1) A certain liquid has a density of 0.80 g/ml. What is the mass of a 40 ml sample of this liquid? 1)

Llana [10]

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 40 mL

density = 0.80 g/mL

The mass is

mass = 40 × 0.8

We have the final answer as

Hope this helps you

8 0

2 years ago