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3 years ago

Explain what happens to the pitch of a cell phone ring when the wavelength of a sound wave increases

Physics

2 answers:

max2010maxim [7]3 years ago

4 0

You get a more low sound.

Conversely, when the wavelength becomes shorter you get a more treble sound.

;-)

andrew-mc [135]3 years ago

4 0

"Pitch" of sound is what we hear as the result of its frequency.

When the wavelength of any sound INcreases, its frequency DEcreases.

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4. Mr. Ames is dragging a box full of books from his office to his car. The box and books together have a

sergey [27]

Answer:

F = 73.7 N = 74 N (rounding off)

Explanation:

In order to get the box to start moving, Mr. Ames must push it with a force equal to the frictional force acting on it. Therefore, this force can be calculated through the following formula:

$F = frictional force = \mu R$

where,

μ = coefficient of friction = 0.55

R = Normal Force on Box = Weight of Box with books = 134 N

Therefore,

$F = (0.55)(134\ N)\\$

<u>F = 73.7 N = 74 N (rounding off)</u>

8 0

2 years ago

100 POINTS+BRAINLIEST: 8TH GRADE SCIENCE - EVAPORATION VS VAPORIZATION: is option B actually wrong? Because vaporization involve

evablogger [386]

Answer:

Explanation:

Vaporization occurs during the boiling/sublimation process. That is the only reason why I could see this being marked as wrong.

5 0

2 years ago

Read 2 more answers

What is electrical power and how is it measured?

Sliva [168]

Answer:

power is measured in watts and its the messure of work over time.

Explanation:

8 0

2 years ago

ListenA bicycle and its rider have a combined mass of 80. kilograms and a speed of 6.0 meters per second. What is the magnitude

Setler [38]

Answer:

a) $1.2\times 10^2\ N$

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

$v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-6}{4}\\\Rightarrow a=-1.5\ m/s^2$

The acceleration of the bicycle and rider is -1.5 m/s²

Force

$F=ma\\\Rightarrow F=80\times -1.5\\\Rightarrow F=-120\ N=-1.2\times 10^2\ N$

The magnitude of the average force needed to bring the bicycle and its rider to a stop is $1.2\times 10^2\ N$

3 0

3 years ago

Army is standing still on the ground; Bill is riding his bicycle at 5 m/s eastward: and Carlos is driving his car at 15 m/s west

Aleks04 [339]

Explanation:

Given that,

Bill is riding his bicycle at 5 m/s eastward: and Carlos is driving his car at 15 m/s westward.

Taking eastward as positive direction, we have:

$v_B=+5\ m/s$ is the velocity of Bill with respect to Amy (which is stationary)

$v_c=15\ m/s$ is the velocity of Carlos with respect to Amy.

Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is

$v_B=+5\ m/s$

Therefore, Carlos velocity in Bill's reference frame will be

$v_c'=-15\ m/s-(+5\ m/s)\\\\=-20\ m/s$

So, the magnitude is 20 m/s and the direction is westward (negative sign).

7 0

3 years ago