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Bogdan [553]
3 years ago
10

Explain what happens to the pitch of a cell phone ring when the wavelength of a sound wave increases

Physics
2 answers:
max2010maxim [7]3 years ago
4 0

You get a more low sound.  

Conversely, when the wavelength becomes shorter you get a more treble sound.

;-)

andrew-mc [135]3 years ago
4 0

"Pitch" of sound is what we hear as the result of its frequency.

When the wavelength of any sound INcreases, its frequency DEcreases.

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___ devices need constant power to operate. The timing functions are initiated by the presence or absence of a separate ""trigge
Ratling [72]

Answer:

Solid-state

Explanation:

A solid-state device can be defined as a crystalline material that is typically made up of semiconductor and as such controls the number and rate of flow of charged carriers such as holes or electrons.

Some examples of a solid-state device are light emitting diodes (LED), integrated circuit (IC), Transistors, liquid crystal display (LCD) etc.

A solid-state device such as a transistor, refers to a semiconductor component that is used to control the flow of voltage or current and as a gate (switch) for electronic signals. Thus, a transistor allows for the amplification, control and generation of electronic signals in a circuit.

Hence, solid-state devices need constant power to operate. The timing functions are initiated by the presence or absence of a separate "trigger" signal.

Basically, these solid-state devices use the optical and electrical properties of semiconductor components such as transistors, triacs, thyristors, diodes to perform its input-output switching and isolation functions.

6 0
3 years ago
Consider an aircraft powered by a turbojet engine that has a pressure ratio of 12. The aircraft is stationary on the ground, hel
agasfer [191]

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3 0
3 years ago
Imagine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and ra
pashok25 [27]

Here if we assume that there is no air friction on both balls then we can say

F = mg

now the acceleration is given as

F = ma = mg

a = g

so here both the balls will have same acceleration irrespective of size and mass

so we can say that to find out the time of fall of ball we can use

y = \frac{1}{2}gt^2

t = \sqrt{\frac{2y}{g}}

now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size

3 0
3 years ago
A spherical soap bubble with a surface-tension of 0.005 lbf/ft is expanded from a diameter of 0.5 in to 3.0 in. How much work, i
Sladkaya [172]

Answer:W = 1.23×10^-6BTU

Explanation: Work = Surface tension × (A1 - A2)

W= Surface tension × 3.142 ×(D1^2 - D2^2)

Where A1= Initial surface area

A2= final surface area

Given:

D1=0.5 inches , D2= 3 inches

D1= 0.5 × (1ft/12inches)

D1= 0.0417 ft

D2= 3 ×(1ft/12inches)

D2= 0.25ft

Surface tension = 0.005lb ft^-1

W = [(0.25)^2 - (0.0417)^2]

W = 954 ×10^6lbf ft × ( 1BTU/778lbf ft)

W = 1.23×10^-6BTU

8 0
3 years ago
A motor keep a Ferris wheel (with moment of inertia 6.97 × 107 kg · m2 ) rotating at 8.5 rev/hr. When the motor is turned off, t
Talja [164]

Answer:

P = 133.13 Watt

Explanation:

Initial angular speed of the ferris wheel is given as

\omega_i = 2\pi f

\omega_i = 2\pi(8.5/3600)

\omega_i = 0.015 rad/s

final angular speed after friction is given as

\omega_f = 2\pi f

\omega_f = 2\pi(7.5/3600)

\omega_f = 0.013 rad/s

now angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{0.015 - 0.013}{15}

\alpha = 1.27 \times 10^{-4} rad/s^2

now torque due to friction on the wheel is given as

\tau = I \alpha

\tau = (6.97 \times 10^7)(1.27 \times 10^{-4})

\tau = 8875.3 N m

Now the power required to rotate it with initial given speed is

P = \tau \omega

P = 8875.3 \times 0.015

P = 133.13 Watt

8 0
3 years ago
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