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vagabundo [1.1K]
3 years ago
15

Fast and safe heart rate for workouts is called muscular strength? True or false

Physics
2 answers:
Vsevolod [243]3 years ago
8 0

Answer:

False

Explanation:

kati45 [8]3 years ago
7 0

Answer:

false :3

hope this helps

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The volume of a gas is 200.0 mL at 275 K and 92.1 kPa. Find its volume at STP.
ycow [4]
To solve this question we will use ideal gas equation:
p*V=n*R*T
Where:
p = pressure
V = volume
n = number of moles
R = gas constant
T = temperature

We can rearrange formula to get:
\frac{p*V}{T} =n*R
We are working woth same gas so we can write following formula. Index 1 stands for conditions before change and index 2 stands for conditions after change.
\frac{ p_{1}*V_{1} }{T_{1}} = \frac{ p_{2}*V_{2} }{T_{2}}

We are given:
p1=92.1kPa = 92100Pa
V1=200mL = 0.2L
T1=275K
p2= 101325Pa
T2=273K
V2=?

We start by rearranging formula for V2. After that we can insert numbers:
{ p_{1}*V_{1} *T_{2}} = { p_{2}*V_{2}*T_{1} } \\  \\ V_{2}= \frac{p_{1}*V_{1} *T_{2}}{ p_{2}*T_{1}}  \\  \\ V_{2}=  \frac{92100*0.2*273}{101325*275}  \\  \\ V_{2}= 0.18L=180mL
7 0
4 years ago
In astronomy which planet spins slowest on its axis​
sertanlavr [38]
Venus - 4 miles per hour
8 0
3 years ago
SOMEONE PLZ HELP. ASAP
Pachacha [2.7K]
Im pretty sure its A
6 0
3 years ago
A bowling ball rolls off the edge of a cliff, moving horizontally at 20 m/s. I have to plot the position of the bowling ball on
liubo4ka [24]
For counting x you use simple equation for the distance covered by the object when it moves with constant velocity:
s=v*t
that gives you 20m after 1st second, 40 m after 2nd second, 60 m after 3rd second and so on.

For counting y you have to use the equation for the distanced covered by the object moving with constantly accelerating velocity (symbols refering to vertical movement):
h=g\frac{t^{2}}{2}
that gives you 5m after 1st second, 20m afters 2nd second, 45m after 3rd second and so on.
Add minus signs before y positions to receive graph presenting the movement of the ball.
So the points are: P1=[20,-5], P2=[40,-20], P3=[60,-45] and so on... Pn=[x,y].
8 0
3 years ago
when two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of
Ahat [919]

<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q​</h2>

Explanation:

Specific heat capacity

It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .

It is given as :

Heat absorbed = mass of substance x specific heat capacity x rise in temperature

or ,

Q= m x c x t

In above question , it is given :

For Q

mass of Q = m

Temperature changed =T₂/2

Heat supplied = x

Q= mc t

or

X=m x C₁ X T₁

or, X =m x C₁ x T₂/2

or, C₁=X x 2 /m x T₂                                 (equation 1 )

For another quantity : P

mass of P =m/2

Temperature= T₂

Heat supplied is same that is : X

so, X= m/2 x C₂ x T₂                            

or, C₂=2X/m. T₂                                   (equation 2 )

Now taking ratio of C₂ to c₁, We have

C₂/C₁= 2X /m.T₂  /2X  /m.T₂

so, C₂/C₁= 1/1

so, the ratio is 1: 1

8 0
4 years ago
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