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3 years ago

Curves on some test tracks and race courses, such as the Daytona International Speedway in Florida, are very steeply banked.

Physics

1 answer:

docker41 [41]3 years ago

8 0

Answer:

Speed, v = 45.84 m/s

Explanation:

Given that,

Radius of the curve, r = 100 m

Banking of the curve, $\theta=65^{\circ}$

On the banking of curve, the speed of the vehicle is given by :

$v=\sqrt{rg\ tan\theta}$

$v=\sqrt{100\times 9.8\times \ tan(65)}$

v = 45.84 m/s

So, the speed at which a 100 m radius curve banked is 45.84 m/s. Hence, this is the required solution.

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As the concentration of a solute in a solution increases, the freezing point of the solution ________ and the vapor pressure of

kykrilka [37]

Answer:

As the concentration of a solute in a solution increases, the freezing point of the solution decrease and the vapor pressure of the solution decrease .

Explanation:

Depression in freezing point :

$\Delta T_f=K_f\times m$

where,

$\Delta T_f$ =depression in freezing point =

$K_f$ = freezing point constant

m = molality ( moles per kg of solvent) of the solution

As we can see that from the formula that higher the molality of the solution is directly proportionate to the depression in freezing point which means that:

If molality of the solution in high the depression in freezing point of the solution will be more.
If molality of the solution in low the depression in freezing point of teh solution will be lower .

Relative lowering in vapor pressure of the solution is given by :

$\frac{p_o-p_s}{p_o}=\chi_{solute}$

$p_o$ = Vapor pressure of pure solvent

$p_s$ = Vapor pressure of solution

$\chi_{solute}$ = Mole fraction of solute

$p_s\propto \frac{1}{\chi_{solute}}$

Vapor pressure of the solution is inversely proportional to the mole fraction of solute.

Higher the concentration of solute more will the be solute's mole fraction and decrease in vapor pressure of the solution will be observed.
lower the concentration of solute more will the be solute's mole fraction and increase in vapor pressure of the solution will be observed.

8 0

3 years ago

Need help I'll give you 30 points please.

Ksivusya [100]

Cathode Ray Tube i think?

7 0

3 years ago

A person lying on an air mattress in the ocean rises and falls through one complete cycle every five seconds. The crests of the

LuckyWell [14K]

Answer:

a) the frequency of the wave is 0.2 Hz

b) the speed of the wave 4 m/s

Explanation:

Given that;

time period = to complete one cycle t = 5 sec

frequency f = 1/t

frequency f = 1 / 5sec

f = 0.2 Hz

Therefore the frequency of the wave is 0.2 Hz

speed of wave V = λf

given that our wavelength is 20.0 m

we substitute

speed of wave V = 20.0 × 0.2

speed of wave V = 4 m/s

Therefore, the speed of the wave 4 m/s

6 0

3 years ago

More than 5 points and will pick brainliest answer plus I will give thanks❗️❕❗️(Don’t answer if you don’t know the answer)

Setler79 [48]

The answer is 2 and 3 because light bulbs dont produce uv rays and uv rays are very dangerous to people.

5 0

4 years ago

A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of

lorasvet [3.4K]

Answer:

19.6 m/s

Explanation:

The parameters given are:

Mass M = 20 Kg

Force F = 285 N

Angle Ø = 30 degree

Time t = 4 seconds

Coefficient of friction = 0.72

At the plane, the weight of the box will be mgsinØ

Resolving forces at the plane, we will have:

MgsinØ + Fr = F

Where Fr = frictional force.

Fr = F - mgsinØ

Substitute all the parameters into the formula

Fr = 285 - 20 × 9.8 sin30

Fr = 285 - 98

Fr = 187 N

But for the box moving toward the top of the plane,

F - Fr = ma

Where a = V/t

Substitute all the parameters involved into the formula

285 - 187 = 20 ( V/4)

98 = 5V

V = 98/5

V = 19.6 m/s

Therefore, the speed with which the box is moving is 19.6 m/s

4 0

3 years ago