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SIZIF [17.4K]
3 years ago
14

Is a theory related to perspective

Physics
1 answer:
lbvjy [14]3 years ago
8 0
A theoretical perspective is a set of assumptions about reality that inform the questions we ask and the kinds of answers we arrive as a result.
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Arada [10]

Answer:D

Explanation: both variables change in the same direction. An increase in one variable leads to an increase in the other, a decrease in one lead to a decrease the another

5 0
4 years ago
Help ASAP please I can’t figure it out and it’s making me stressed
marysya [2.9K]

Explanation:

may I ask what it is on because I might be able to help out

5 0
3 years ago
Problem 5 A block of mass 3 kg slides on a horizontal, rough surface towards a spring with k = 500 N/m. The kinetic friction coe
vredina [299]

Answer:

Explanation:

given,

mass of block = 3 kg

spring constant k = 500 N/m

kinetic friction coefficient µk = 0.6

speed of block = 5 m/s

F = µk  N

F = 0.6 x 3 x 9.8

F = 17.64 N

using energy conservation

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2+Fx

\dfrac{1}{2}\times 3 \times 5^2=\dfrac{1}{2}\times 500 \times x^2+17.64\times x

250 x² + 17.64 x - 37.5 = 0

on solving

x = 0.354 m

graph is attached below

4 0
4 years ago
Read 2 more answers
If a skier travels at a constant velocity downhill, this means the forces on her are: ................. A. Zero B. Negligible C.
Vlad1618 [11]

Answer:

F = 0

Explanation:

The net force acting on an object is given by the product of mass and acceleration. We know that acceleration is equal to the rate of change of velocity.

Net force,

F = ma

F=\dfrac{m(v-u)}{t}

The skier is traveling at a constant velocity, it means there is no change in velocity i.e. acceleration is equal to 0. Hence, the force on her is 0.

7 0
3 years ago
A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During
Artemon [7]

Answer:

Induced EMF,\epsilon=0.0143\ volts

Explanation:

Given that,

Radius of the circular loop, r = 5 cm = 0.05 m

Time, t = 0.0548 s

Initial magnetic field, B_i=200\ mT=0.2\ T

Final magnetic field, B_f=300\ mT=0.3\ T

The expression for the induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=\dfrac{d(BA)}{dt}

\epsilon=A\dfrac{d(B)}{dt}

\epsilon=A\dfrac{B_f-B_i}{t}

\epsilon=\pi (0.05)^2\times \dfrac{0.3-0.2}{0.0548}

\epsilon=0.0143\ volts

So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.

5 0
3 years ago
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