Answer:
<h2>980000ft-lbs</h2>
Explanation:
Step one:
given data
mass of cable= 4lb/ft
mass of coal= 1000lb
dept of mine= 700ft
Step two:
Required
the work-done to lift the coal and the rope combined
Work-done to lift coal
Wc=1000*700= 700,000 lb-ft
Work-done to lift rope
substitute y=700 we have, since y=0 will result to 0
I'm guessing "measure skill" means "the ability to measure things." In reality, all experiments by necessity require data and typically we need to measure things to get them (even if this is done by devices, programs or computers). When doing science labs, you'll likely need to use scales, pipets, and various glasswear to measure different things. Even if you're used to using a ruler, getting a really good measurement that you can feed into equations and get meaningful results from requires a bit of practice and more care than you might think. I'd also say that the measurement skill comes into play when making approximations or assumptions about experiment. No measurement is infinitely accurate, you can't measure the width of an atom with a standard 12 inch ruler, or if you did, you'd have to have a very large amount of error. Making these logical conclusions about your devices, where they reach their limits, and what potential error you may have and where it comes from are all important when doing science.
Answer:
a) 33.6 min
b) 13.9 min
c) Intuitively, it takes longer to complete the trip when there is current because, the swimmer spends much more time swimming at the net low speed (0.7 m/s) than the time he spends swimming at higher net speed (1.7 m/s).
Explanation:
The problem deals with relative velocities.
- Call Vr the speed of the river, which is equal to 0.500 m/s
- Call Vs the speed of the student in still water, which is equal to 1.20 m/s
- You know that when the student swims upstream, Vr and Vs are opposed and the net speed will be Vs - Vr
- And when the student swims downstream, Vr adds to Vs and the net speed will be Vs + Vr.
Now, you can state the equations for each section:
- distance = speed × time
- upstream: distance = (Vs - Vr) × t₁ = 1,000 m
- downstream: distance = (Vs + Vr) × t₂ = 1,000 m
Part a). To state the time, you substitute the known values of Vr and Vs and clear for the time in each equation:
- (Vs - Vr) × t₁ = 1,000 m
- (1.20 m/s - 0.500 m/s) t₁ = 1,000 m⇒ t₁ = 1,000 m / 0.70 m/s ≈ 1429 s
- (1.20 m/s + 0.500 m/s) t₂ = 1,000 m ⇒ t₂ = 1,000 m / 1.7 m/s ≈ 588 s
- total time = t₁ + t₂ = 1429s + 588s = 2,017s
- Convert to minutes: 2,0147 s ₓ 1 min / 60s ≈ 33.6 min
Part b) In this part you assume that the complete trip is made at the velocity Vs = 1.20 m/s
- time = distance / speed = 1,000 m / 1.20 m/s ≈ 833 s ≈ 13.9 min
Part c) Intuitively, it takes longer to complete the trip when there is current because the swimmer spends more time swimming at the net speed of 0.7 m/s than the time than he spends swimming at the net speed of 1.7 m/s.
