Answer:
Induced emf, 
Explanation:
The varying magnetic field with time t is given by according to equation as :

Where
are constant
Let
is the emf induced in the loop as a function of time. We know that the rate of change of magnetic flux is equal to the induced emf as:





So, the induced emf in the loop as a function of time is
. Hence, this is the required solution.
Answer:
work = 1125 [J]
Explanation:
To solve this problem we must remember the definition of power, which is defined as the relationship between work and time. The power can be calculated using the following equation:
Power = work/time
Power = 12.5 [w]
work = joules [J]
time = 1.5 [min] = 90 [s]
work = 12.5*90
work = 1125 [J]
Answer:
A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change of strength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.