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4 years ago

A wave has a wavelength of 10mm and a frequency of 5 hz what is the speed?

2 answers:

4 0

thats not one of the answers that is provided so its pretty much wrong unless you meant 0.50 mm/s other than that its wrong.

geniusboy [140]4 years ago

3 0

V=fλ
v=5*0.01
Therefore v=0.05

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Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una a

kolbaska11 [484]

Answer:

Velocidad final, V = 8 m/s

Explanation:

Dados los siguientes datos;

Velocidad inicial, u = 4 m/s

Aceleración, a = 2 m/s²

Tiempo, t = 2 segundos

Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;

V = u + at

Sustituyendo en la fórmula, tenemos;

V = 4 + 2*2

V = 4 + 4

Velocidad final, V = 8 m/s

6 0

3 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this

Ne4ueva [31]

Answer:

In order to hit the same point with the second ball, you should throw it at an angle of 18° above the horizontal.

Explanation:

Horizontal reach formula for projectiles tells us

$d=\frac{v_i^2\sin(2\theta)}{g},$

where $v_i$ is the initial velocity and $\theta$ the angle above the horizontal.

Since for both shots the reach must be the same, we have

$\frac{v_i^2\sin(2\theta_1)}{g}=\frac{v_i^2\sin(2\theta_2)}{g}\\\sin(2\theta_1)=\sin(2\theta_2)\\\theta_2=\frac{1}{2}\arcsin(\sin(2\theta_1))=\frac{1}{2}\arcsin(\sin(2\times 72\deg))=\mathbf{18\deg}$ .

8 0

4 years ago

1) a cathode-ray tube is a type of ______ tube.

galina1969 [7]

1) Vacuum tube
2) silicon
3) integrated, I.C.s
4) this one is worded weird. Transistors are the main part of voltage regulators but they use (require) diodes and capacitors, too. And they are all put onto a microchip in the power distribution section. sorry for the long explanation.
5) away from
6) directly, inversely

4 0

3 years ago

During a hard drive crash the read/write head scrapes against the disk with a coefficient of kinetic friction of µk and normal f

Alex_Xolod [135]

Answer:

α = $\frac{2 \mu \ N}{m \ r}$

Explanation:

For this exercise we use Newton's equation for rotational motion

∑ τ = I α

the troque is

α = Fr .r

the moment of inertia of a cylinder is

I = ½ m r²

we substitute

fr r = (½ m r²) α

the expression friction is

fr = μ N

we substitute

μ N r = ½ m r² α

α = $\frac{2 \mu \ N}{m \ r}$

3 0

3 years ago

Please help

lukranit [14]

A ray box is the answer I give

3 0

3 years ago