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dmitriy555 [2]
3 years ago
10

A wave has a wavelength of 10mm and a frequency of 5 hz what is the speed?

Physics
2 answers:
8090 [49]3 years ago
4 0

thats not one of the answers that is provided so its pretty much wrong unless you meant 0.50 mm/s other than that its wrong.

geniusboy [140]3 years ago
3 0
V=fλ
v=5*0.01
Therefore v=0.05
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A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
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Answer:

The average emf that will be induced in the wire loop during the extraction process is 37.9 V

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The average emf induced can be calculated from the formula

Emf = -N\frac{\Delta \phi}{\Delta t}

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The change in magnetic flux is given by

\Delta \phi = \phi _{f} - \phi _{i}

Where \phi _{f} is the final magnetic flux

and \phi _{i} is the initial magnetic flux

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\phi = BAcos(\theta)

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and \theta is the angle between the magnetic field and the area.

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From the question,

B = 1.5 T

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A = \pi r^{2}

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A = 0.0225\pi

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\phi_{i}  = (1.5)(0.0225\pi)

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\phi_{i}  = 0.03375\pi Wb

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The field pointed upwards, that is \theta = 90^{o}. Since cos (90^{o}) = 0

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\phi_{f} = 0

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\Delta \phi = 0- 0.03375\pi

\Delta \phi = - 0.03375\pi

From the question

\Delta t = 2.8 ms = 2.8 \times 10^{-3} s

Here, N = 1

Hence,

Emf = -N\frac{\Delta \phi}{\Delta t} becomes

Emf = -(1)\frac{-0.03375\pi}{2.8 \times 10^{-3} }

Emf = 37.9 V

Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.

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Answer:

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