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4 years ago

So to find a base by its formula, does it end in COO or COOH? Can a base be both of those endings?

Chemistry

1 answer:

sleet_krkn [62]4 years ago

3 0

Answer:

To find a base by its formula, does it end in COO-

A base never ens with COOH

Explanation:

According to Bronsted Acid - Base theory : When an acid and base reacts with each other , the acid form its conjugate base and base will form its conjugate acid because of exchange of proton .

If HA = acid and B = base react each other then they generate their conjugate Base (A-) and acid (HB+) respectively .

The equation is represented as :

$HA+B\rightleftharpoons A^{-}+HB^{+}$

Here A- is conjugate base of HA acid

HB+ is conjugate acid of base B

COOH group is the carboxylic acid group = acid

Suppose A carboxylic acid RCOOH is added in water(H2O)

$RCOOH + H_{2}O\rightleftharpoons RCOO^{-}+H^{+}$

Here

RCOOH = Acid and its conjugate -base is RCOO-

Hence A Base end with formula COO-

COOH is always acid

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JulijaS [17]

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3 years ago

Read 2 more answers

A 20g sample of iron at a temperature of 120oC is placed into a container of water. There are 300 milliliters of water in the co

galben [10]

Answer:

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

$-Q_1=Q_2$

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Specific heat capacity of iron = $c_1=0.444 J/g^oC$

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Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

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Density of water = 1 g/mL

Mass of water= $m_2=300 mL\times 1 g/mL = 300 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=30^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

we get, T = 30.63°C

30.63 °C will be the final temperature of the water.

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4 years ago

Using the equation 2H2+O2 = 2H2I, if 192 g if oxygen reacts completely, how many grams of hydrogen must react with it

dimaraw [331]

I assume there is a typo in the equation. It is H2O instead of H2I.

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4 years ago