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balandron [24]
3 years ago
10

For the following questions consider a piece of copper wire. a. What type of bond is formed between the copper atoms? b. Describ

e how these bonds form. c. Explain why copper is a good electrical conductor.
Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

metallic bond

sea of delocalized electrons

Explanation:

Copper has Cu2+ atoms arranged in layers and held together by a sea of electrons in lattice form. The sea of electrons or de-localized electrons are provided by Cu. Each copper atom contributes 2 electrons to the sea for binding of Cu2+ atom layer.

The sea of electrons are highly mobile and require a very small potential difference across the atoms to push these electrons to form a current. The mobility, ease and freeness of these electrons allows copper to be a good electrical conductor

yarga [219]3 years ago
6 0

Answer:

a. metallic bond

b. the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “cloud” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

c. due to the presence of free electrons in its outer energy levels

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Two uniform solid spheres of the same size, but different mass, are released from rest simultaneously at the same height on a hi
SpyIntel [72]

Answer:

options A and C

Explanation:

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4 0
3 years ago
Can someone help label these?
seropon [69]
A. reactants
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7 0
2 years ago
Calculate the potential difference across a 25- resistor if a 0.3-A current is flowing through it.
alekssr [168]

Voltage = (current) x (resistance)

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8 0
3 years ago
Read 2 more answers
A ship's wheel has a moment of inertia of 0.930 kilogram·meters squared. The inner radius of the ring is 26 centimeters, and the
Vikki [24]

We can use the formula of the moment of inertia given by:

r\cdot F=I\alpha

Where:

r = Distance from the point about which the torque is being measured to the point where the force is applied

F = Force

I = Moment of inertia

α = Angular acceleration

So:

\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}

Answer:

12 rad/s²

8 0
1 year ago
PLEASE HELP ME I JUST CAN'T FIGURE THIS ONE OUT
kupik [55]
Indeed the answer is c!!
4 0
3 years ago
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