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balandron [24]
3 years ago
10

For the following questions consider a piece of copper wire. a. What type of bond is formed between the copper atoms? b. Describ

e how these bonds form. c. Explain why copper is a good electrical conductor.
Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

metallic bond

sea of delocalized electrons

Explanation:

Copper has Cu2+ atoms arranged in layers and held together by a sea of electrons in lattice form. The sea of electrons or de-localized electrons are provided by Cu. Each copper atom contributes 2 electrons to the sea for binding of Cu2+ atom layer.

The sea of electrons are highly mobile and require a very small potential difference across the atoms to push these electrons to form a current. The mobility, ease and freeness of these electrons allows copper to be a good electrical conductor

yarga [219]3 years ago
6 0

Answer:

a. metallic bond

b. the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “cloud” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

c. due to the presence of free electrons in its outer energy levels

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Explanation:

The given data is as follows.

         mass (m) = 170 kg,        Distance (s) = 9.6 m

        Height (h) = 3.3 m,         Force (F) = 1400 N

First, we will calculate the work performed by her as follows.

                W = Fs

                    = 1400 N \times 9.6 m

                    = 13440 J

Hence, minimal work necessary to lift the refrigerator is as follows.

               U = mgh

                   = 170 kg \times 9.8 \times 3.3 m

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Therefore, we can conclude that he performed 5497.8 J of work.

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A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken
MAXImum [283]

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

v^{2} = u^{2} + 2as

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

0^{2} = 20^{2} + 2(10)s

Rearrange for s

0^{2} -20^{2} =20s

-400=20s

\frac{-400}{20} =s

s = -20 (The negative is just showing direction, it can be ignored for now)

The height reached is 20m

Use a different equation to find the time taken

s = vt - \frac{1}{2} at^{2}

Substitute in the values we have

-20=(0)t - \frac{1}{2} (10)t^{2}

Rearrange for t

-20 =0 -5 t^{2}

\frac{-20}{-5} =t^{2}

4 = t^{2}

t = 2s

The time taken to reach 20m is 2 seconds

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