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4 years ago

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Physics

1 answer:

fomenos4 years ago

4 0

Answer:

The bulbs should be connected in parallel.

Explanation:

We want to find out a way to hook up 2 light bulbs and a battery so that when one bulb burns out or is disconnected the other bulbs stays lit.

We must connect the two bulbs in parallel so that even when one bulb is burns out, it will have no effect on the other bulb and the 2nd bulb will keep on working. The current flowing in each bulb will depend upon the resistance of each bulb and the voltage will be same across each bulb.

On the other hand, if we use a series circuit then if one bulb burns out then the there is no flow of current in the circuit and therefore, the second bulb will not be operational.

The current flowing through each bulb is given by

I = V/R

The voltage across each bulb is given by

V = IReq

Where I is the current and Req is the equivalent resistance of the two bulbs connected in parallel and is given by

Req = (R₁*R₂)/(R₁+R₂)

The connection diagram is attached where two bulbs are connected in parallel and are power with a battery.

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A industrial (large) pressure cooker operates at 275 kPa. Initially there is 10 kg of water at 20Â°C, the cooker is operated unt

alex41 [277]

Answer:

$Q_{in} = 25349.92\,kJ$

Explanation:

Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:

$Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}$

The heat transfered to the cooker is:

$Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}$

Properties at each state are described below:

State 1

$u_{1} = 83.913\,\frac{kJ}{kg}$

$h_{1} = 83.915\,\frac{kJ}{kg}$

State 2

$u_{2} = 2540.1\,\frac{kJ}{kg}$

$h_{2} = 2720.9\,\frac{kJ}{kg}$

The heat transfered to the cooker is:

$Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )$

$Q_{in} = 25349.92\,kJ$

7 0

3 years ago

The potential energy for a certain mass moving in one dimension is given by U(x)=(2.0J/m3)x3−(15J/m2)x2+(36J/m)x−23JU(x)=(2.0J/m

Angelina_Jolie [31]

Answer:x=2 and x=3

Explanation:

Given

Potential Energy for a certain mass is

$U(x)=2x^3-15x^2+36x-23$

and we know force is given by

$F=-\frac{\mathrm{d} U}{\mathrm{d} x}$

$F=-(2\times 3x^2-15\times 2x+36)$

For Force to be zero F=0

$\Rightarrow 6x^2-30x+36=0$

$\Rightarrow x^2-5x+6=0$

$\Rightarrow x^2-2x-3x+6=0$

$\Rightarrow (x-2)(x-3)=0$

Therefore at x=2 and x=3 Force on particle is zero.

8 0

3 years ago

describe a method you would use to separate chicken soup into other forms of matter from which its made of

nexus9112 [7]

Heat it until it evaporates(Gas) :3
Or freeze it until its ice.(Solid)
its already a liquid normally

Unless you mean like separate the noodles from the broth, in that case use a drainer :'D Jk. I suck at smart stuff.

3 0

3 years ago

How is the work done to hoist the counterweight related to the potential energy of the counterweight at its specified height?

Nesterboy [21]

Answer:

The work done to lift the counterweight equals the potential energy acquired

Explanation:

since this is vertically applied force on the counterweight, and the distance the force is displacing the counterweight is in the same direction as the applied force, it equals the gained potential energy

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3 years ago

Two objects made of the same material are heated to 60 oC and 90 oC. According to

nlexa [21]

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3 years ago

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