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4 years ago

5

Two charged objects are separated by distance, d. The first charge has a larger magnitude (size) than the second charge. Which o

ne exerts the most force?

1 answer:

maw [93]4 years ago

8 0

Pretty sure the first one

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Consider a uniformly charged non-conducting semicircular arc with radius r and total negative charge Q. The charge on a small se

Mazyrski [523]

Answer: Magnitude of electric field = 6.77×10^11N/C

Explanation: Electric field= E =KQ/ r ^2

Given:

Total charge Q=53.2nc

Radius 84cm= 0.84m

Coulombs constant K= 8.987x10^9NmC^-1

E =(( 8.987×10^9) × 53.2) /(0.84^2)

E = ( 4 . 777 ×10 ^ 9 )/ 0.7056

E = 6.77 × 10^ 11 NC^-1

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3 years ago

Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out

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Answer:

The two value of the wavelength for the out of tune guitar is

$\lambda _2 = (6.48,6.52) \ cm$

Explanation:

From the question we are told that

The wavelength of the note is $\lambda = 6.50 \ cm = 0.065 \ m$

The difference in beat frequency is $\Delta f = 17.0 \ Hz$

Generally the frequency of the note played by the guitar that is in tune is

$f_1 = \frac{v_s}{\lambda}$

Where $v_s$ is the speed of sound with a constant value $v_s = 343 \ m/s$

$f_1 = \frac{343}{0.0065}$

$f_1 = 5276.9 \ Hz$

The difference in beat is mathematically represented as

$\Delta f = |f_1 - f_2|$

Where $f_2$ is the frequency of the sound from the out of tune guitar

$f_2 =f_1 \pm \Delta f$

substituting values

$f_2 =f_1 + \Delta f$

$f_2 = 5276.9 + 17.0$

$f_2 = 5293.9 \ Hz$

The wavelength for this frequency is

$\lambda_2 = \frac{343 }{5293.9}$

$\lambda_2 = 0.0648 \ m$

$\lambda_2 = 6.48 \ cm$

For the second value of the second frequency

$f_2 = f_1 - \Delta f$

$f_2 = 5276.9 -17$

$f_2 = 5259.9 Hz$

The wavelength for this frequency is

$\lambda _2 = \frac{343}{5259.9}$

$\lambda _2 = 0.0652 \ m$

$\lambda _2 = 6.52 \ cm$

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Quoting from the article itself:

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3 years ago

Which one is it? WIll mark brainlist

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Answer:

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Explanation:

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