Answer:
Explanation:
Well you have the voltages right, and that is no trivial matter. Each one of the resistors in a parallel circuit sees the same input voltages (in this case 6).
Now I think it would be a good idea to fill in the the resistance column.
R1 = 3 ohms
R2 = 6 ohms
R3 = 2 ohms
The total resistance can be calculated in two ways. I'll get around to doing both of them but I'll do the conventional way first. One hint: the total resistance must be smaller than the smallest resistor. Read that sentence over a couple of times. What it means is that it must be less than 2 ohms in a parallel circuit.
1/r1 + 1/r2 + 1/r3 = 1/rt
1/3 + 1/6 + 1/2 = 1/rt
Change all the denominators to 6ths.
2/6 + 1/6 + 3/6 = 1/rt
(2 + 1 + 3)/6 = 6/6 = 1
rt = 1
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So the current I is V/R
V = 6
R = 1
Current = V/R = 6/1 = 6 amps.
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The current in each resistor is
I1 = V / R1
I1 = 6/3 = 2 amps
I2 = V/R2
I2 = 6/6 = 1 amp
I3 = 6/2 = 3 amps
The total is I1 + I2 + I3 = 2 + 1 + 3 = 6 amps.
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Remember I said there was 2 ways of figuring out the total resistance. I did one of them about. Here's the other.
R = V / It
R = 6 / 6
R = 1 ohm just what you got before.
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Power
P = V * I
P1 = 6 * 2 = 12 watts
P2 = 6*1 = 6 watts
P3 = 6*3 = 18 watts
Pt = 36 watts.
Pt can be done by using the voltage * the total current
Pt = 6 volts * 6 amps = 36 watts, just what you would expect.
