1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OverLord2011 [107]
3 years ago
13

Can you complete and EXPLAIN please?????:(

Physics
1 answer:
jonny [76]3 years ago
3 0

Answer:

Explanation:

Well you have the voltages right, and that is no trivial matter. Each one of the resistors in a parallel circuit sees the same input voltages (in this case 6).

Now I think it would be a good idea to fill in the the resistance column.

R1 = 3 ohms

R2 = 6 ohms

R3 = 2 ohms

The total resistance can be calculated in two ways. I'll get around to doing both of them but I'll do the conventional way first. One hint: the total resistance must be smaller than the smallest resistor. Read that sentence over a couple of times. What it means is that it must be less than 2 ohms in a parallel circuit.

1/r1 + 1/r2 + 1/r3 = 1/rt

1/3 + 1/6 + 1/2 = 1/rt

Change all the denominators to 6ths.

2/6 + 1/6 + 3/6 = 1/rt

(2 + 1 + 3)/6 = 6/6  = 1

rt = 1

====================

So the current I is V/R

V = 6

R = 1

Current = V/R = 6/1 = 6 amps.

====================

The current in each resistor is

I1 = V / R1

I1 = 6/3 = 2 amps

I2 = V/R2

I2 = 6/6 = 1 amp

I3 = 6/2 = 3 amps

The total is I1 + I2 + I3 = 2 + 1 + 3 = 6 amps.

======================

Remember I said there was 2 ways of figuring out the total resistance. I did one of them about. Here's the other.

R = V / It

R = 6 / 6

R = 1 ohm just what you got before.

====================

Power

P = V * I

P1 = 6 * 2 = 12 watts

P2 = 6*1   = 6 watts

P3 = 6*3 = 18 watts

Pt =            36 watts.

Pt can be done by using the voltage * the total current

Pt = 6 volts * 6 amps = 36 watts, just what you would expect.

You might be interested in
what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​
Reil [10]

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

3 0
3 years ago
Read 2 more answers
An electron is moving at 2.02.0 ×× 105m/s105 m/s in the positive y direction. The magnetic force on the electron is 3.03.0 ×× 10
inn [45]

Answer:

The magnitude and direction of the magnetic field is 93.63 T in negative x direction.

Explanation:

Given;

speed of the electron in positive y direction, v = 2.0 x 10⁵ m/s

magnetic force on the electron, F in negative z direction = 3.0 x 10⁻¹² N

The magnitude of the magnetic force is given by;

F = Qv x B

B = F / Qv

B = \frac{3*10^{-12}}{ (1.602*10^{-19})(2*10^5)}\\\\B = 93.63 \ T

The direction of the magnetic field is is as;

Based on the direction of magnetic force (negative z direction), the charge will be directed into negative y-direction because electron is negatively charged. Thus, the direction of the magnetic field will be in the negative x-direction

F_{(-z)}= Q_{(-y)}V* B_{(-x)}

Therefore, the magnitude and direction of the magnetic field is 93.63 T in negative x direction.

6 0
2 years ago
1. Acceleration can result from a change of _______, or a change in ___________, or both *
Klio2033 [76]

Answer:

not sure

Explanation:

jahhhhhsjjjjdddddhdhdj hbdbd#dialectical DHL I have no clue W Bush administration and I don't have any jshshhhhdgggddddddd the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

jsbsbd the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

the entire community was literate because

a. they had been slaves and had not been to school

b. they were too poor to go to school

c. work was more important to them than education

d. they avoided to going school

BFF and I don't have any questions please call her and her husband to the hospital for a bit more time with my family grew up in the form of a ring whose inner circumference is it a lot of people who are you doing today beautiful and I don't have any questions please call her and her husband to the

4 0
3 years ago
Two objects carry initial charges that are q1 and q2, respectively, where |q2| > |q1|. They are located 0.160 m apart and beh
mart [117]

Answer:

\rm |q_1|=8.0\times 10^{-7}\ C,\ \ \ |q_2| = 4.6\times 10^{-6}\ C.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force between two static point charges  \rm q_1 and \rm q_1, separated by a distance \rm r, is given by

\rm F = \dfrac{kq_1q_2}{r^2}.

where k is the Coulomb's constant.

Initially,

\rm r = 0.160\ m\\F_i = -1.30\ N.\\\\and \ \ |q_2|>|q_1|.

The negative sign is taken with force F because the force is attractive.

Therefore, the initial electrostatic force between the charges is given by

\rm F_i = \dfrac{kq_1q_2}{r^2}.\\-1.30=\dfrac{kq_1q_2}{0.160^2}\\\rm\Rightarrow q_2 = \dfrac{-1.30\times 0.160^2}{q_1k}\ \ \ ..............\ (1).

Now, the objects are then brought into contact, so the net charge is shared equally, and then they are returned to their initial positions.

The force is now repulsive, therefore, \rm F_f = +1.30\ N.

The new charges on the two objects are

\rm q_1'=q_2' = \dfrac{q_1+q_2}{2}.

The new force is given by

\rm F_f = \dfrac{kq_1'q_2'}{r^2}\\+1.30=\dfrac{k\left (\dfrac{q_1+q_2}{2}\right )\left (\dfrac{q_1+q_2}{2}\right )}{0.160^2}\\\Rightarrow \left (\dfrac{q_1+q_2}{2}\right )^2=\dfrac{+1.30\times 0.160^2}{k}\\(q_1+q_2)^2=\dfrac{4\times 1.30\times 0.160^2}{k}\\q_1^2+q_2^2+2q_1q_2=\dfrac{4\times 1.30\times 0.160^2}{k}\\\\

Using (1),

\rm q_1^2+\left ( \dfrac{-1.30\times 0.160^2}{q_1k}\right )^2+2\left (\dfrac{-1.30\times 0.160^2}{k} \right )=\dfrac{4\times 1.30\times 0.160^2}{k}\\q_1^2+\dfrac 1{q_1^2}\left ( \dfrac{-1.30\times 0.160^2}{k}\right )^2-\left (\dfrac{6\times 1.30\times 0.160^2}{k} \right )=0\\q_1^4+\left ( \dfrac{-1.30\times 0.160^2}{k}\right )^2-q_1^2\left (\dfrac{6\times 1.30\times 0.160^2}{k} \right )=0

\rm q_1^4+\left ( \dfrac{-1.30\times 0.160^2}{k}\right )^2-q_1^2\left (\dfrac{6\times 1.30\times 0.160^2}{k} \right )=0\\q_1^4+\left ( \dfrac{-1.30\times 0.160^2}{9\times 10^9}\right )^2-q_1^2\left (\dfrac{6\times 1.30\times 0.160^2}{9\times 10^9} \right )=0\\q_1^4-q_1^2\left (\dfrac{6\times 1.30\times 0.160^2}{9\times 10^9} \right )+\left ( \dfrac{-1.30\times 0.160^2}{9\times 10^9}\right )^2=0

\rm q_1^4-q_1^2\left (2.22\times 10^{-11} \right )+\left ( 1.37\times 10^{-23}\right ) =0\\\Rightarrow q_1^2 = \dfrac{-(-2.22\times 10^{-11})\pm \sqrt{(-2.22\times 10^{-11})^2-4\cdot (1)\cdot (1.37\times 10^{-23})}}{2}\\=1.11\times 10^{-11}\pm 1.046\times 10^{-11}.\\=6.4\times 10^{-13}\ \ \ or\ \ \ 2.156\times 10^{-11}\\\Rightarrow q_1 = \pm 8.00\times 10^{-7}\ C\ \ \ or\ \ \ \pm 4.64\times 10^{-6}\ C.

Using (1),

When \rm q_1 = \pm 8.00\times 10^{-7}\ C,

\rm q_2=\dfrac{-1.30\times 0.160^2}{\pm 8.00\times 10^{-7}\times 9\times 10^9}=\mp4.6\times 10^{-6}\ C.

When \rm q_1=\pm 4.6\times 10^{-6}\ C,

\rm q_2=\dfrac{-1.30\times 0.160^2}{\pm 4.64\times 10^{-6}\times 9\times 10^9}=\mp7.97\times 10^{-7}\ C\approx 8.0\times 10^{-7}\ C.

Since, \rm |q_2|>|q_1|

Therefore, \rm |q_1|=8.0\times 10^{-7}\ C,\ \ \ |q_2| = 4.6\times 10^{-6}\ C.

7 0
2 years ago
Explain how neurons convey information using both electrical and chemical signals.
8090 [49]

Answer:

Explanation:

Neurons communicate via both electrical signals and chemical signals. The electrical signals are action potentials, which transmit the information from one of a neuron to the other; the chemical signals are neurotransmitters, which transmit the information from one neuron to the next.

The electrical signal travels down the axon to the axon terminals where it tells the vesicles to release the neurotransmitters into the synaptic cleft which travel to the receptors of the receiving cell which releases the second messengers

6 0
3 years ago
Other questions:
  • An investigator places a sample 1.0 cm from a wire carrying a large current; the strength of the magnetic field has a particular
    9·1 answer
  • What is the bending of a wave around a barrier?
    5·1 answer
  • A bullet is fired vertically into a 1.40 kg block of wood at rest directly above it. if the bullet has a mass of 29.0 g and a sp
    10·1 answer
  • If the skater coasts only around 65 degrees of the circle, find the magnitude of his displacement vector.
    15·1 answer
  • Which of the following is an agent of socialization?
    7·2 answers
  • most of earth water a. contains salt b.is freshwater c. is frozen in glaciers d. is found underground​
    12·2 answers
  • A child is prescribed a drug X; the recommended manufacturer’s dose is 2.50 mg/m2. The body surface area (BSA) of the child is 1
    11·1 answer
  • Match the glacier feature with its description.
    5·2 answers
  • The scientific principle involve in the inflation of an airbag. Explain how this Device protects the drivers and the front passe
    8·1 answer
  • To transform electrical energy into mechanical energy, the electromagnet in a
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!