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Brilliant_brown [7]
3 years ago
8

The pressure of 4.2L of nitrogen gas in a flexible container is decreased to one-half its original pressure and its absolute tem

perature is increased to double the original temperature what is tge volume now
Chemistry
1 answer:
hram777 [196]3 years ago
7 0

Answer:

V₂ = 16.8V₁

Explanation:

P₁ = 4.2L   =>   P₂ = 1/2P₁ => Decreasing Pressure => Increases Volume

V₁ = V₁      =>    V₂ = ?

T₁ = T₁       =>    T₂ = 2T₁  => Increasing Temperature => Increases Volume

P₁V₁/T₁ = P₂V₂/T₂ => V₂ = P₁V₁T₂ / P₂T₁ = (4.2P₁)(V₁)(2T₁) / (P₁/2)(T₁) = 16.8V₁

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Answer:

V_2=12.1L

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

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Then, we obtain:

V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L

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The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


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