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babymother [125]
3 years ago
6

Using the correct number of significant figures 52.733 multiplied by 48.21

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

2542

Rule for multiplying Significant Figures:

  • The product is limited to the number of sig figs equal to the least number of sig figs in the problem

Explanation:

52.733 has 5 significant figures and 48.21 has 4 significant figures. Therefore, the answer given must have 4 significant figures.

52.733(48.21) = 2542.25793

This answer round to have 4 significant figures is 2542.

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An oxide of nitrogen contains 30.45 mass % N.
N76 [4]

An oxide of nitrogen contains 30.45 mass % N, if the molar mass is 90± 5 g/mol the molecular formula is N₂O₄.

<h3>What is molar mass?</h3>

The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. A substance's molar mass is one of its properties. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes.

<h3>How to find the molecular formula?</h3>

The whole-number multiple is defined as follows.

Whole-number multiple = \frac{molar mass (g/mol)}{empirical formula mass (g/mol)}

The empirical formula mass is shown below.

Mw of empirical formula = Mw of N+ 2 x (Mw of O)

                                      = 14.01 g/mol + 2 x (16.00 g/mol)

                                      = 46.01 g/mol

With the given molar mass or the molecular formula mass, we can get the whole-number multiple for the compound.

Whole-number multiple = \frac{90 g/mol }{46.01 g/mol} ≈ 2

Multiplying the subscripts of NO2 by 2, the molecular formula is N(1x2)O(2x2)= N2O4.

To learn more about molar mass visit:

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5 0
2 years ago
An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume
liberstina [14]

Answer:

M KIO3 = 1.254 mol/L

Explanation:

  • molarity (M) [=] mol/L

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L

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Answer:

option A

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