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babymother [125]
3 years ago
6

Using the correct number of significant figures 52.733 multiplied by 48.21

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

2542

Rule for multiplying Significant Figures:

  • The product is limited to the number of sig figs equal to the least number of sig figs in the problem

Explanation:

52.733 has 5 significant figures and 48.21 has 4 significant figures. Therefore, the answer given must have 4 significant figures.

52.733(48.21) = 2542.25793

This answer round to have 4 significant figures is 2542.

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Oceans cover over 70% of Earth's surface, and precipitation constantly adds freshwater to the oceans. Yet, ocean levels remain r
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Answer:

D.

Explanation:

I had looked it up on the quiz site

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If the volume of 0.100M HCl delivered to 10.0mL of NaOH is 12.0mL the NaOH concentration is
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<span>During neutralization reaction Milliequivalent of acid=milliequivalent of base. Milliequivalent of HCl=0.100*12*1 Milliequivalent of NaOH=M*10*1 So 0.100*12*1=M*10*1 Solve for M.</span>
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In the simulation, open the Micro mode, then select the solutions indicated below from the dropdown list above the beaker. The b
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Answer:

In order of basicity we have

1. Soda pop (Least basic Normally called acidic)

2. Orange juice

3. Milk

4. Blood (slightly basic)

5. Hand soap

6. Drain cleaner (Highly basic)

Explanation:

Orange juice; the pH of orange juice is in the 3.3 to 4.2 range

Milk; the pH of milk about 6.5 to 6.7

Blood; the blood pH is around 7.35 to 7.45

Hand soap with contents such as ammonium hydroxide is basic, its  pH is about 9-10

Drain cleaner contains baking soda or sodium bicarbonate which basic with a  pH of 12 to 14

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Arranging the above listed in order of increasing basicity, we have

1. Soda pop

2. Orange juice

3. Milk

4. Blood

5. Hand soap

6. Drain cleaner

6 0
2 years ago
386 g ÷ 20cm3 what is density
tatyana61 [14]
22.3 is the answer to this question
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3 years ago
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A geochemist in the field takes a 46.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
inysia [295]

Answer:

The solubility of the mineral compound X in the water sample is 0.0189 g/mL.

Explanation:

Step 1: Given data

The volume of water sample = 46.0 mL.

The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.

Step 2: Calculate the solubility of X in water

46.00 mL of water sample contains 0.87 g of the mineral compound X.

To calulate how many grams of the mineral compound  1.0 mL  of water sample contains:

0.87 g/46.0 mL = 0.0189 g.

This means the solubility of the mineral compound X in the water sample is 0.0189 g/mL.

3 0
3 years ago
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