ΔG° at 450. K is -198.86kJ/mol
The following is the relationship between ΔG°, ΔH, and ΔS°:
ΔH-T ΔS = ΔG
where ΔG represents the common Gibbs free energy.
the enthalpy change, ΔH
The temperature in kelvin is T.
Entropy change is ΔS.
ΔG° = -206 kJ/mol
ΔH° equals -220 kJ/mol
T = 298 K
Using the formula, we obtain:
-220kJ/mol -T ΔS° = -206kJ/mol
220 kJ/mol +206 kJ/mol =T ΔS°.
-T ΔS = 14 kJ/mol
for ΔS-14/298
ΔS=0.047 kJ/mol.K
450K for the temperature Completing a formula with values
ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol
ΔG° = -220 kJ/mol + 21.14 kJ/mol.
ΔG°=198.86 kJ/mol
Learn more about ΔG° here:
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Carbonic anhydrase speeds up<span> the transfer of carbon dioxide from cells to the blood.
Hope this work cuz</span>
Answer:
![\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctext%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
Explanation:
At the beginning, you have two reactions happening:
As you add KOH(aq), it does two things:
- It increases the volume of the solution.
- It reacts with the hydronium ions to form water.
A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.
B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.
C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.
D) As HClO₂ reacts, it forms ClO₂⁻. ![\boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctextbf%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
Answer:
(a )people separate mixtures in order to ger a specific substance that they need.
Answer:
B 2Li + Cl2 ---> 2LiCl
Explanation:
There are 2 Li atoms and 2 Cl atoms on both sides of the equation.
