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Afina-wow [57]
3 years ago
8

What is the connection between diamonds and stardust?

Chemistry
1 answer:
Ede4ka [16]3 years ago
8 0

According to an article dated back in February 8, 1992 which is entitled, “Science: Stardust is made of diamonds” on a website called newscientist (https://www.newscientist.com/article/mg13318073-000-science-stardust-is-made-of-diamonds/), American astronomers believed that diamonds are made in supernova explosions. It was said that the diamonds were the foundation of uncommon combinations of isotopes found in some meteorites. Donald Clayton of Clemson University in South Carolina suggested that the weightiest isotopes were more common in meteorites for the reason that the rare gases shaped in the neutron-rich outcome of a supernova explosion. Clayton also said, “the observed mixture of isotopes could have been produced only during the collapse of a massive star to form a neutron star”. This happens in a Type II explosion, for example the Supernova 1987A in the Large Magellanic Cloud. And rare gases like xenon become stuck in both weighty and light isotopes after the ejected gas from such a supernova cools down enough to create dust. The existence of the diamonds with these unusual gases in meteorites infers an alike source. Some of the carbon in the supernova fragments produces ordinary graphite dust, whereas some produces diamond dust. Considerable amount of stardust may be made of diamonds, if Clayton was not mistaken.

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Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

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And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

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<u>Answer:</u>

<u>For a:</u> The chemical equation for the dissolution of sodium carbonate is Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)

<u>For b:</u> The net acid-base reaction is CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)

<u>Explanation:</u>

  • <u>For a:</u>

Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.

The chemical equation for the dissolution of sodium carbonate follows:

Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)

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CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)

Hence, the net acid-base reaction of the anion formed and water is written above.

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