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2 years ago

100 POINTS!!!

Chemistry

2 answers:

Paul [167]2 years ago

6 0

what do u need help with u pls respond quickly

Pie2 years ago

3 0

Different masses will change its temperature at different rates when exposed to the same amount of thermal energy because the amount of mass affects an object’s ability to absorb thermal energy. Different materials will change the temperature at different rates when exposed to the same amount of thermal energy because each substance has its own specific heat.

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What temperature does vodka freeze in fahrenheit?

zhuklara [117]

The answer is -11.2 fahrenheit.

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4 years ago

A student pipets 10 ml of a 0.0693 m solution of kbr into a 500 ml volumetric flask and dilutes to the mark. what is the concent

Sonja [21]

The initial concentration of solution is 0.0693 M. The volume of solution taken is 10 mL and it is diluted to a final volume of 500 mL.

According to dilution law, the product of initial concentration and volume is equal to the product of final concentration and volume as follows:

$C_{1}V_{1}=C_{2}V_{2}$

Here, $C_{1}$ is initial concentration, $C_{2}$ is final concentration, $V_{1}$ is initial volume and $V_{2}$ is final volume.

Rearranging to calculate final concentration,

$C_{2}=\frac{C_{1}\times V_{1}}{V_{2}}$

Putting the values,

$C_{2}=\frac{0.0693 M\times 10 mL}{500 mL}=0.001386 M$

Therefore, concentration of the resulting solution is 0.001386 M.

7 0

3 years ago

Calculate the energy (in joules) of each photon that is emitted from a patch of ground that is at 32 ∘C. Use the λmax of that te

AlekseyPX

Attached response

hope that helps!

3 0

3 years ago

Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu

katrin2010 [14]

Answer:

$T2=276K$

Explanation:

Given:

Initial volume of the balloon V1 = 348 mL

Initial temperature of the balloon T1 = 255C

Final volume of the balloon V2 = 322 mL

Final temperature of the balloon T2 =

To calculate T1 in kelvin

T1= 25+273=298K

Based on Charles law, which states that the volume of a given mass of a ideal gas is directly proportional to the temperature provided that the pressure is constant. It can be applied using the below formula

$(V1/T1)=(V2/T2)$

T2=( V2*T1)/V1

T2=(322*298)/348

$T2=276K$

Hence, the temperature of the freezer is 276 K

8 0

3 years ago

A Question 2 (2 points) Retake question

Ksivusya [100]

Answer:

3.3765 Mol O2

Explanation:

There is no work for this problem

3 0

3 years ago