Answer:
Hope this helps:)
Explanation:
Your exercise: Step by step:
1*225/88*r*a=1*(0/-1)*e+1*(__/88)*r*a | If the numerator equals zero, the fraction will be zero
1*225/88*a*r=1*0*e+1*(__/88)*r*a | Multiply 0 by e. Any number multiplied by 0 is 0.
1*225/88*a*r=0+1*__/88*r*a | Multiply __/88 by a. You can multiply a fraction by a number by multiplying the number and the numerator.
1*225/88*a*r=0+1*__*a*a*r | Multiply (__*a)/88 by r. You can multiply a fraction by a number by multiplying the number and the numerator.
1*225/88*a*r=0+1*(__*a*r)/88 | · 88
1*225*a*r=88*(__*a*r)/88 | Multiply 88 by (__*a*r)/88. You can multiply a fraction by a number by multiplying the number and the numerator.
225*a*r=88*(__*a*r)/88 | Cancel (__*88*a*r)/88 with 11*2^3
225*a*r=(__*a*r)/1 | Numerator 1 of (__*a*r)/1 can be omitted .
225*a*r=1*__*a*r | : 225
1*a*r=1*__*0.004*a*r | Divide both sides by a .
1*r=1*(__*0.004*a*r)/a
The beta particle is represented by the Greek letter <span>β. The beta particle is one of the particles that are emitted during radioactive decay. Beta particles are emitted in the process of beta decay. A beta particle can be in form of an electron or a positron. </span><span />
Answer:
94.3 grams
Explanation:
MW of C2HF3O2 is 114g/mol
MW of oxygen in C2HF3O2 is 32g/mol
% composition of oxygen in C2HF3O2 = 32/114 × 100 = 28.1%
Mass of oxygen = 26.5 grams
Mass of trifluoroacetic acid = 26.5/0.281 = 94.3 grams
no
<u>Explanation:</u>
i simply answered the question
you didnt ask for it you simply asked if i had it
being mad is no use, same with reporting and taking this down
in thoery my answer is correct
so, dont get mad, dot report, dont take this down
<u><em>this is my protest</em></u>
It’s dependent on light-dependent products ATP and NADPH which aren’t present at night
