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Ann [662]
3 years ago
11

I’m just doing this because it told me to in order to get the answer for my homework?

Chemistry
2 answers:
andrew-mc [135]3 years ago
7 0
Ok good luck on your homework then
Sladkaya [172]3 years ago
6 0
You need to post your problem before it can be answered
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Increasing the temperature of a chemical equilibrium system that naturally releases heat in the forward direction will _________
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<span>I think D. shift the equilibrium reaction to favor the endothermic process. </span>
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3 years ago
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If mass increases and volume stays the same, then density will _________.
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As size increases<span> or decreases, </span>DENSITY REMAINS THE SAME<span>! As a rule, things that are MORE dense will sink or fall to the bottom of things that are LESS dense (think of oil and water). ... Notice that </span>if<span> you DECREASE the </span>mass<span> of something or</span>INCREASE<span> the </span>volume<span>, the </span>density<span> will be less…</span>
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3 years ago
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Can you describe the situations when Greek prefixes are used?
Black_prince [1.1K]

Answer:

Here's what I get  

Explanation:

At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.

They indicate the number of atoms or groups in a molecule when you are naming a compound.

1. Binary covalent compounds

For example, P₂S₅ is diphosphorus pentasulfide.

2. Hydrates

For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.

7 0
3 years ago
What types of materials are usually ductile
White raven [17]
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7 0
4 years ago
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What mass of iron (III) nitrate will be in 129.8ml of a 0.3556 molar aq iron (III) nitrate solution?
Anvisha [2.4K]

<u>Answer:</u> The mass of iron (III) nitrate is 11.16 g/mol

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.3556 M

Molar mass of Iron (III) nitrate = 241.86 g/mol

Volume of solution = 129.8 mL

Putting values in above equation, we get:

0.3556M=\frac{\text{Mass of iron (III) nitrate}\times 1000}{241.86 g/mol\times 129.8}\\\\\text{Mass of iron (III) nitrate}=11.16g

Hence, the mass of iron (III) nitrate is 11.16 g/mol

6 0
3 years ago
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