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Ann [662]
3 years ago
11

I’m just doing this because it told me to in order to get the answer for my homework?

Chemistry
2 answers:
andrew-mc [135]3 years ago
7 0
Ok good luck on your homework then
Sladkaya [172]3 years ago
6 0
You need to post your problem before it can be answered
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What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

6 0
3 years ago
Which compound would you expect to be soluble in the nonpolar solvent carbon disulfide?
ch4aika [34]

Answer:

hexane C6H14

IS YOUR ANSWER

Explanation:

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8 0
3 years ago
Mathias Schleiden, one of the writers of the cell theory, studied _________ tissue and noticed that every sample he looked at wa
JulijaS [17]
You need to put there “poetry “
8 0
3 years ago
Read 2 more answers
1. Calculate the attractive bonding force for NaF and for MgO when the ions just touch. Based on the attractive bonding force, w
Andreas93 [3]

Answer:

The attractive force is negative and MgO has a higher melting point

Explanation:

From Couloumb's law:

Energy of interaction, E = k \frac{q1q2}{r}

where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.

If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).

In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten

The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.

Hence the compound MgO would have a higher melting point than NaF.

5 0
4 years ago
Write the expression for the equilibrium constant for the reaction represented by the equation CaCO3(s)⇌Ca2+(aq)+CO32−(aq). Is K
Alexeev081 [22]

<u>Answer:</u> For the given reaction, the value of K_c is greater than 1

<u>Explanation:</u>

For the given chemical equation:

CaCO3(s)\rightleftharpoons Ca^{2+}(aq.)+CO_3^{2-}(aq.)

The expression of K_c for above equation follows:

K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression

As, the denominator is missing and the numerator is the only part left in the expression. So, the value of K_c will be greater than 1.

Hence, for the given reaction, the value of K_c is greater than 1

5 0
4 years ago
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