Answer:
<em>Gases tend to deviate from ideal gas law at </em><u><em>high pressures and low temperatures.</em></u>
Explanation:
The main statements from molecular kinetic theory to describe an ideal gas is that 1) the gas particles occupy a neglictible fraction of the total volume of the gas, and 2) there is not force of attraction between gas particles.
HIgh pressure means that the gas particles will be forced closer to each other, making that the mean distance between the particles be realtively more important and their volume less neglictible. This is a violation the first assumption described above.
Since the temperature is directly related to the kinetic energy, and the latter with the movement of the particles (average speed), low temperatures lead to the molecules being less independent of each other, i.e. the forces between the molecules will count more . This fact constitutes a violation of the second principle established in the first paragraph.
In <u>conclusion</u>, <em>high pressures and low temperatures tend to deviate gases from the ideal gas law.</em>
You can read more about ideal and real gases behavior on brainly.com/question/12449772
Answer:
In which [Ag+] in negligibly small and the concentration of each reactant is 1.0 M
The answer is A) PO43- < NO3- < Na+
Explanation:
Ag+ is removed from the solution just like PO43-, so there are just 2 possible answers at this point: a or b. Then we can notice that Na3PO4 releases 3 moles of Na+ and just 1 mole of NO3-
We have 100mL of each reactant with the same concentration for both (1.0 M) so:
(0.1)(1)(3)= 0.3 mol Na+
(0.1)(1)= 0.1 mol NO3-
so PO43- < NO3- < Na+
Answer:
[HI] = 0.7126 M
Explanation:
Step 1: Data given
Kc = 54.3
Temperature = 703 K
Initial concentration of H2 and I2 = 0.453 M
Step 2: the balanced equation
H2 + I2 ⇆ 2HI
Step 3: The initial concentration
[H2] = 0.453 M
[I2] = 0.453 M
[HI] = 0 M
Step 4: The concentration at equilibrium
[H2] = 0.453 - X
[I2] = 0.453 - X
[HI] = 2X
Step 5: Calculate Kc
Kc = [Hi]² / [H2][I2]
54.3 = 4x² / (0.453 - X(0.453-X)
X = 0.3563
[H2] = 0.453 - 0.3563 = 0.0967 M
[I2] = 0.453 - 0.3563 = 0.0967 M
[HI] = 2X = 2*0.3563 = 0.7126 M