All categories

2 years ago

5.Are pure solids included in equilibrium expressions? Explain your answer.

Chemistry

1 answer:

tatiyna2 years ago

8 0

Answer:

Pure solids or liquids are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction. The concentration of a pure liquid or solid equals its density divided by its molar mass.

Explanation:

Hope this helps!!!

You might be interested in

The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C

avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

$q=c\times (T_{final}-T_{initial})$

where,

q = heat gained = ?

c = specific heat = $5.20kJ/^oC$

$T_{final}$ = final temperature = $27.43^oC$

$T_{initial}$ = initial temperature = $22.93^oC$

Now put all the given values in the above formula, we get:

$q=5.20kJ/^oC\times (27.43-22.93)^oC$

$q=23.4kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = $\frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole$

$\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole$

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

$\Delta H=\Delta U+\Delta n_gRT$

or,

$\Delta U=\Delta H-\Delta n_gRT$

where,

$\Delta H$ = change in enthalpy = $-2805.8kJ/mol$

$\Delta U$ = change in internal energy = ?

$\Delta n_g$ = change in moles = 0 (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = $27.43^oC=273+27.43=300.43K$

Now put all the given values in the above formula, we get:

$\Delta U=\Delta H-\Delta n_gRT$

$\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K$

$\Delta U=-2805.8kJ/mol-0$

$\Delta U=-2805.8kJ/mol$

Therefore, the internal energy change is -2805.8 kJ/mol

5 0

3 years ago

In what ways are the two designs in part C different? How do you think these differences will relate to the ability of each desi

Ilya [14]

The top one is different from the bottom because of is curvature shape while the bottom one is a square shape i think the bottom will heat up faster because of the nice even area inside where heat waves can evenly flow

4 0

2 years ago

Will mark brilliant pls help question is above

Degger [83]

Answer:

a.) The garden plants provide energy to all the other organisms. While not every organism consumes garden plants directly, every organism's food lineage can be traced to garden plants. For instance, while ground beetles do not directly consume garden plants, they do eat snails, and snails eat garden plants.

b.) The slug population might increase is the aphid population decreased because there would be less competition for food resources. Both populations consume garden plants, and there is only a finite number of garden plants. Therefore, there is a limit that each population can consume. If there were less aphids eating the garden plants, there would be more left for the slugs. Less starving slugs would lead to greater reproduction and thus a higher slug population.

4 0

2 years ago

Which is a physical change?

ira [324]

Making toast is a physical change.

*** Please mark this answer as the Brainliest and leave a Thanks if I helped you! :) ***

4 0

3 years ago

Read 2 more answers

List the primary consumers in the food web please help

Masja [62]

Answer: