Answer:
C. They are exergonic and provide energy that can be used to produce ATP form ADP and Pi.
Explanation:
There are 2 types of metabolic reactions.
- Anabolic reactions (Anabolism)
- Catabolic reactions (Catabolism)
CATABOLIC REACTIONS:
They consist of reactions in which larger molecules are broken down into simpler ones. They are exergonic i.e. energy producing reactions. The released energy can be stored in the form of ATP (energy currency of cell).
ANABOLIC REACTIONS:
They consist of reactions in which larger molecules are synthesized from simpler ones. They are endergonic reactions i.e. energy is absorbed.
MEMORY AID:
An easy way to remember catabolic reactions is to think of them as "catastrophic reactions" i.e. larger molecules are destructed to produce simpler ones.
Coming back to the question,
<u>a. They require energy from ATP hydrolysis to break down polymers into monomers. </u>
Energy requiring reactions are anabolic and so this is the incorrect answer.
<u>b. They are endergonic and release energy that can be used for cellular work.</u>
Endergonic reactions are anabolic and hence this is the incorrect answer.
<u>c. They are exergonic and provide energy that can be used to produce ATP from ADP and Pi</u>
This statement correctly fits the definition of Catabolic reactions and is therefore the correct answer.
<u>d. They combine small molecules into larger, more energy-rich molecules.</u>
This statement describes anabolic reactions and hence the incorrect choice.
Answer:
Explanation:
Hello,
In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:
Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:
Best regards.
Answer:
For disodium hydrogen phosphate:
5.32g Na2HPO4
For sodium dihydrogen phosphate:
7.65g Na2HPO4
Explanation:
First, you have to put all the data from the problem that you going to use:
-NaH2PO4 (weak acid)
-Na2HPO4 (a weak base)
-Volume = 1L
-Buffer pH = 7.00
-Concentration of [NaH2PO4 + Na2HPO4] = 0.100 M
What we need to find the pKa of the weak acid, in this case NaH2PO4, for that you need to find the Ka (acid constant) of NaH2PO4, and for this we use the pKa of the phosphoric acid as follow:
H3PO4 = H2PO4 + H+ pKa1 = 2.14
H2PO4 = HPO4 + H+ pKa2 = 6.86
HPO4 = PO4 + H+ pKa3 = 12.4
So, for the preparation of buffer, you need to use the pKa that is near to the value of the pH that you want, so the choice will be:
pKa2= 6.86
Now we going to use the Henderson Hasselbalch equation for the pH of a buffer solution:
pH = pKa2 + log [(NaH2PO4)/(Na2HPO4)]
The solution of the problem is attached to this answer.
Answer:
A = 2A + 3B → 5C
Explanation:
The two molecule of A and three molecules of B will react to form the five molecules of C.
2A + 3B → 5C
Other options are incorrect because,
B = A₂ + B₃ → C₅
in this reaction one molecule of A₂ and one molecule of B₃ combine to form one molecule of C₅.
C = 2A + 5B → 3C
in this reaction two molecules of A and five molecules of B combine to form three molecule of C.
D = A₂ + B₃ → C₃
in this reaction one molecule of A₂ and one molecule of B₃ combine to from one molecule of C₃.
Answer: Option (e) is the correct answer.
Explanation:
Formula to calculate radius is as follows.
p(r) = 
= 
= 0
+ 
= 0
= 
r = 
Thus, we can conclude that most likely radius at which the electron would be found is .
