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viva [34]
3 years ago
15

Autoionization occurs when two solvent molecules collide and a proton is transferred between them. Write the autoionization reac

tion for acetic acid, CH3COOH.
Chemistry
1 answer:
Ghella [55]3 years ago
4 0

Answer:

<h3>2CH3COOH(l)⇒⇒⇒⇒(CH3COOH2)+ + (CH3COO)-</h3>

Explanation:

Remember that, ionization is a process by which an atom or a molecule receives a negative or positive charge by gaining or losing electrons during a chemical reaction. However the auto-ionization reaction for acetic acid the two solvent molecules (CH3COOH2)+ + (CH3COO-) collide and a proton is transferred between them.

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Calculate the energy of a quantum of radiant energy with a frequency of 5.00x1011/s
Aloiza [94]
5.00 x  1011/s = 5.05500kilohertz
7 0
3 years ago
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A solution is made by dissolving 23.5 grams of glucose (C6H12O6) in 0.245 kilograms of water. If the molal freezing point consta
aalyn [17]

Answer:

- 0.99 °C ≅ - 1.0 °C.

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

m is the molality of the solution (m = moles of solute / kg of solvent = (23.5 g / 180.156 g/mol)/(0.245 kg) = 0.53 m.

<em>∴ ΔTf = (Kf)(m)</em> = (-1.86 °C/m)(0.53 m) =<em> - 0.99 °C ≅ - 1.0 °C.</em>

4 0
4 years ago
The combination of potassium-sparing diuretics and salt substitutes can result in dangerously high blood levels of:
alisha [4.7K]

Answer:

b. potassium.  

Explanation:

Potassium-sparing diuretics and salt substitutes are diuretics that eliminate salt and water but save potassium. They act by inhibiting the conducting sodium channels in the collecting tubule, such as amiloride and triamterene, or by blocking aldosterone, such as spironolactone.

Concomitant use of potassium-sparing diuretics together with salt substitutes may result in dangerously high blood levels of serum potassium. For this reason, it is important to consult a physician before taking these substances at the same time to avoid potential problems with potassium accumulation.

4 0
3 years ago
You have a 250. -ml sample of 1. 28 m acetic acid (ka = 1. 8 x´ 10–5). calculate the ph of the best buffer.
Nadya [2.5K]

The ph of the best buffer is 4.74

The given acetic acid is a weak acid

The equation of the pH of the buffer

pH = pKa + log ( conjugate base / weak acid ).

For best buffer the concentration of the weak acid and its conjugate base is equal.

pH = pKa + log 1

pH = pKa + 0

pH = pKa

given Ka = 1.8 × 10⁻⁵

pKa = - log ka

pH = -log ( 1.8 × 10⁻⁵ )

pH = 4. 74

Hence the pH of the best buffer is 4.74

Learn more about the pH on

brainly.com/question/22390063

#SPJ4

4 0
2 years ago
Read 2 more answers
Please please !!! help me I’ve been doing this for 2 hours
MatroZZZ [7]

Answer:

3.7 x 10^23

is the right answer

6 0
3 years ago
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