Considering the combustion reaction of propane again, what mass of propane (C3Hg) is necessary to react with 4.53 g of oxygen? C
1 answer:
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Answer:
<h2>Density = 0.00026 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
<h3>From the question
mass of air = 1.2 g
volume = 4,555 mL
Substitute the values into the above formula and solve for the density
That's
<h3>= 0.0002634
We have the final answer as
<h3>Density = 0.00026 g/mL</h3>Hope this helps you