Considering the combustion reaction of propane again, what mass of propane (C3Hg) is necessary to react with 4.53 g of oxygen? C
3H8 +5023CO₂ + 4H₂O 0.0256 g C3H8 1.13 g C3H8 1.25 g C3H8 2.50 g C3H8
1 answer:
Answer:
1.25 g C3H8
Explanation:
edge lol
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Answer:
1.30atm
Explanation:
P1/T1 = P2/T2
1.07/393 = P2/478
Answer:
A. N2S3
yep u r right
Explanation:
Dinitrogen Trisulfide N2S3 Molecular Weight -- EndMemo.
The answer is B. Fungi,Protists
Definitely definite mass because liquids can take on any shape and can have different volumes.
Oxygen had 6 valence electrons
