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Rainbow [258]
2 years ago
11

-2y+x=2y-8 what is the y-int and x-int?

Mathematics
1 answer:
skad [1K]2 years ago
6 0

Answer:

x-intercept (-8,0)

y-intercept (0,2)

Step-by-step explanation:

To find the x-intercept, you set y equal to 0.

Like this:

-2(0)+x=2(0)-8

  0  +x=0    -8

        x=   -8

So the x-intercept is (-8,0).

To find the y-intercept, you set x equal to 0.

Like this:

-2y+0=2y-8

  -2y =2y-8

Subtract 2y on both sides

 -4y=-8

Divide both sides by -4

   y=2

So the y-intercept is (0,2)

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I need help with this
34kurt

Answer:

it would be (-8,14)

Step-by-step explanation:

so if you plot it on a graph all ypu would do is flip it over the x axis

4 0
3 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
2 years ago
Read 2 more answers
-3 (9x +20) > 15x -20
KengaRu [80]
-27x - 60 > 15x - 20
+27x  +20   +27x +20

-40= 42x

-20
----- = x                            Is this correct?
 21
3 0
3 years ago
What is the answer to this problem 1/2=q 2/3?
Angelina_Jolie [31]
3/2 = 2q
q = 3/2 ÷ 2
q = 3/2 × 1/2
q = 3/4
6 0
3 years ago
A tree is leaning at a 5° angle from vertical, making an 85° angle with the ground. When the sun is at a 65° angle of elevation,
Vinvika [58]
D = 25 ft is the length of a shadow. L -  the length of a tree.
Two angles are 85° and 65° and the third is 180° - ( 65° + 85° ) =
= 180° - 150° = 30°.
We will use the Sine Law:
25 / sin 30° = L / sin 65°
25 / 0.5 = L / 0.9063
25 * 0.9063 = 0.5 L
22.6577 = 0.5 L
L = 22.6577 : 0.5
L = 45.3 ft.
Answer: the approximate length of the tree is 45.3 ft.


3 0
3 years ago
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