There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
Learn more about combinations at brainly.com/question/11732255
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Answer:
30.2 is the answer (use distrubutyion in this problem)
Step-by-step explanation:
Answer:
Set 1 Angle A is 90
Set 1 Angle B is 45
Set 2 Angle B is 15
Set 2 Angle C is 90
2)
Set 1 Angles A and C are both 62
Set 2 Angles B and D are both 120
Step-by-step explanation:
We can use the Pythagorean Theorem to solve for side AB
a^2+b^2=c^2
a will be 6 and b will be 8 becuase those are the legs
6^2+8^2=c^2
36+64=c^2
100=c^2 (square root both sides)
c=10
Then we find the difference between 10 and 6 because 6 is the shortest leg
10-6=4 ft. so B
Hope this helps
Idk I just need to answer some more questions