Given:

Chemistry

1 answer:

marusya05 [52]4 years ago

7 0

Answer:

92.6 g.

Explanation:

The balanced equation is:

CaC₂ + N₂ → CaCN₂ + C.

It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.

We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:

n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.

We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.

∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.

<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>

Now, we can get the grams of N₂ consumed to produce 265.0 g of CaCN₂:

∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.

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Natali5045456 [20]

The question is incomplete, the complete question is :

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