If a 12-N force is applied continuously through a distance
of 12m, then the amount of work done is
(force) x (distance) = (12 N) x (12 m) = 144 joules.
Power = (work done) / (time to do the work)
= (144 joules) / (3 sec) = 48 joules/sec = 48 watts.
We don't care what purpose the force was used for,
or how much friction was involved.
1) 29.8 C
At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).
2) 6.2 C
The temperature change of the water is given by the difference between its final temperature and its initial temperature:
where
Substituting into the formula,
And the positive sign means that the temperature of the water has increased.
3) -40.6 C
The temperature change of the metal is given by the difference between its final temperature and its initial temperature:
where
Substituting into the formula,
And the negative sign means the temperature of the metal has decreased.
Answer: Point A is the answer for the potential energy. Point D is the answer for the kinetic energy.
Explanation:
A lower, easier gear, with the smaller chain ring up front and a largercog in the back, lets you accelerate faster.
Decomposition reactions are said to be those reactions in which a reactants breakdown into two or more products. The general reaction for decomposition reactions is as follow,
ABC → A + B + C
Specific Examples are as,
Water → Hydrogen + Oxygen
2 H₂O → 2 H₂ + O₂
Calcium carbonate → Calcium oxide + Carbon dioxide
CaCO₃ → CaO + CO₂
While, Synthetic reactions are said to be those reactions in which two or more reactants combine to form two or more products. The general reaction for synthetic reactions is as follow,
A + B + C → ABC
Specific Examples are as,
Iron + Oxygen → Iron Oxide
2 Fe + 3 O₂ → 2 Fe₂O₃
Sodium + Chlorine → Sodium chloride
2 Na + Cl₂ → 2 NaCl
Sulfur + Oxygen → Sulfur dioxide
S + O₂ → SO₂
Potassium + Chlorine → Potassium chloride
2 K + Cl₂ → 2 KCl