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solong [7]
4 years ago
7

A rectangular parking lot has an area of 7/10 km 2.The width is 1/3 km 2 .What is the length of the parking lot written as a imp

roper fraction ,in kilometers
Mathematics
1 answer:
lora16 [44]4 years ago
3 0

Answer:

\dfrac{21}{10}\text{ km}.

Step-by-step explanation:

It is given that,

Area of rectangular plot =\dfrac{7}{10}\text{ km}^2

Width of rectangular plot =\dfrac{1}{3}\text{ km}

We need to find the length of the parking lot.

We know that,

\text{Area of rectangle}=length\times width

\dfrac{7}{10}=length\times \dfrac{1}{3}

\dfrac{7\times 3}{10}=length

length=\dfrac{21}{10}

Therefore, length of the parking lot is \dfrac{21}{10}\text{ km}.

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Answer:

a) 6.68% of heights less than 150 centimeters

b) 58.65% of heights between 160 centimeters and 180 centimeters

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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a) The percentage of heights less than 150 centimeters

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Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 162}{8}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

6.68% of heights less than 150 centimeters

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We have to find the pvalue of Z when X = 180 subtracted by the pvalue of Z when X = 160.

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Z = \frac{160 - 162}{8}

Z = -0.25

Z = -0.25 has a pvalue of 0.4013

0.9878 - 0.4013 = 0.5865

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