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trapecia [35]
3 years ago
14

An apple that was 4 meters off the ground was blown off a tree. The angle between the final position of the apple and the origin

al
position of the apple was 35
4 m
35
Note: picture not drawn to scale
Which equation can be used to find the horizontal distance, r, that the apple was displaced?
Mathematics
1 answer:
Bond [772]3 years ago
4 0

Answer:

Tan35°=4m/r

Step-by-step explanation:

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The angle turns through 1-9 of the circle
Diano4ka-milaya [45]
What does that mean I don't get it I will randomly guess 500000000
6 0
4 years ago
2. The function A(n)=5+(n-1) (4) represents an arithmetic sequence.
kirza4 [7]

Answer:

1. D.

2. A. + F.

3. B.

3 0
4 years ago
Which equation correctly uses point (–2, –6) to write the equation of this line in point-slope form? Y – 6 = y minus 6 equals St
Tanya [424]

Answer:

Step-by-step explanation:

The standard way of writing equation of a line in a point-slope form is as given;

y - y0 = m(x-x0)

m is the slope of the line

(x0,y0) is a point on the line.

Given the point (-2,-6), in order to determine with of the equation that correctly uses the point, we will substitute the point into the formula and get the necessary equation.

y - y0 = m(x-x0)

y - (-6) = m(x-(-2))

y+6 = m(x+2)

Since we are not given the slope, let's assume the slope is 5/2

The equation becomes y+6 =5/2(x+2). Option D is correct

8 0
4 years ago
What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y
Mumz [18]

Answer:

\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

Step-by-step explanation:

The question is poorly formatted.

Given

\sqrt[3]{2y^3} * 7\sqrt{18y}

Required

Derive an equivalent expression

\sqrt[3]{2y^3} * 7\sqrt{18y}

Express 18 as 9 * 2

\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}

Split the expression as follows:

\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}

Take positive square root of 9

\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}

\sqrt[3]{2y^3} * 21 * \sqrt{2y}

21*\sqrt[3]{2y^3} *  \sqrt{2y}

The cube root can be rewritten to give:

21*\sqrt[3]{2}*\sqrt[3]{y^3} *  \sqrt{2y}

\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y

So, we have:

21*\sqrt[3]{2} * y *  \sqrt{2y}

Rewrite as:

21y *\sqrt[3]{2}  *  \sqrt{2y}

Split \sqrt{2y

21y *\sqrt[3]{2}  *  \sqrt{2} * \sqrt{y}

Collect Like Terms

21y*\sqrt{y} *\sqrt[3]{2}  *  \sqrt{2}

Represent in index form

21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}

Apply law of indices

21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }

21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}

21*y^{\frac{3}{2}} *2^{\frac{5}{6}}

21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

Hence:

\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})

6 0
3 years ago
The question is in the picture. The answer is 14 but I don't know how to get that.
andrezito [222]
Let's convert the problem into Arithmetic progression:
It would be: 5, 9, 13, .... 

Here, a = 5, d = 9 - 5 = 4
We know, S(n) = n/2 [ 2a + (n-1)d ]

Substitute the known values, 
434 = n/2 [ 2(5) + (n - 1)4 ]
434 * 2 = n [ 10 + 4n - 4 ]
868 = 10n + 4n² - 4n
= 4n² + 6n - 868 = 0

d = b² - 4ac
d = 6² - 4(4)(-868)
d = 36+13888
d = 13924

Now, roots = -b +- √d / 2a
= (-6 + √13924) / 2(4)   OR  (-6 - √13924) / 2(4)
= (-6 + 118) / 8   OR  (-6 - 118) / 8
= 112/8  OR  -124/8
= 14 OR -15.5

As number of sticks can't be in negative/decimal or fraction form, -15.5 would be fully rejected.

In short, Your Answer would be 14 [ Remaining root ]

Hope this helps!
7 0
3 years ago
Read 2 more answers
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