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olga_2 [115]
3 years ago
15

Josh works in a balloon store. He will put 45 balloons into bunches. He must use the same number of balloons in each bunch. The

number of balloons in each bunch must be greater than 1 and less than 10. How many balloons could be in each bunch?
Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0

Answer: 5, 9

Factors of 45:

  • 1
  • 5
  • 9
  • 15
  • 45

5 and 9 are between 1 and 10.

They are the answers.

5 x 9 = 45

9 x 5 = 45

kaheart [24]3 years ago
4 0

Answer: 5 or 9

Find the factors of the number 45.

1, 5, 9, 15

The numbers must be greater than 1 and less than 10.

Now, we must take 5 and 9.

5 x 9 = 45

9 x 5 = 45

The answers are 5 & 9.

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Diano4ka-milaya [45]

Answer:

B

Step-by-step explanation:

Starting with 7,000, after 0 years there will be no increase so you still have 7,000.

The fist year you increase by 5% of 7,000.

.05x7000=350

You have a 350 increase, add that to the original 7000 to find the actual population after 1 year (domain value 1).

After 1 year: 7350

For year 2 there is an increase of 5% again, only this time we find 5% of 7350 since that was the previous years population.

.05x7350=368

Add that to previous population.

368+7350=7718

At this point so far the yearly populations have been (7000, 7350, 7718)

Answer choice B is the only one to have this progression.

3 0
3 years ago
If two angles are both obtuse, the two angles are equal
yan [13]
If two angles are equal, then the two angles are obtuse.

5 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
Help me please find the answer
dangina [55]
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3 0
3 years ago
Gregory has a credit card with a 30-day billing cycle and an APR of 11.95%. The following table shows Gregory’s credit card tran
Luba_88 [7]
Adjusted balance = 622.82 - 45.45 + 78.91 + 16.36 = 672.64
Adjused balance method finance charges = 672.64 x 0.1195/12 = 6.70

Average daily balance = ((622.82 x 3) + (577.37 x 6) + (656.28 x 15) + 672.64 x 6)) / 30 = (1868.46 + 3464.22 + 9844.20 + 4035.84) / 30 = 640.42
Daily balance method finance charges = 640.42 x 0.1195/12 = 6.38
3 0
3 years ago
Read 2 more answers
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