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allsm [11]
3 years ago
5

Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average

speed is 55 miles per hour. The 2nd departs Seattle at the same time that the first one departs San Francisco. Its average speed is 65 miles per hour. The length of track separating the two locations is 860 miles. How many minutes (from departure time) before the two trains collide?
Physics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

7,166 hrs =430  minutes

Explanation:

Since both train are on the same track, going one towards the other, the relative speed is the addition of both, then the time they need to meet, and consistently crash, is the time that (65mph + 55 mph)=120mph need to travel the total distance of 860 miles, of course in this case one part is traveled by the first train and the rest by the other. Then to find the time we use a three rule

1 h --->120mi

X ---->860mi, then X=(860 mi* 1h)/120 mi = 43/6 hrs= 7,16666 hrs, turning this into minutes need that we notice 1h=60min, then 43/6 hrs *60 min/hrs = 430 minutes.

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A machinist is required to manufacture a circular metal disk with area 1300 cm2. (a) What radius produces such a disk
vichka [17]

Answer:

Radius r = 20.34 cm

The radius that can produces such a disk is 20.34 cm

Explanation:

Area of a circle;

A = πr^2

A = area

r = radius

Making r the subject of formula;

r = √(A/π) ........1

Given;

A = 1300 cm^2

Substituting into the equation 1;

r = √(1300/π)

r = 20.34214472564 cm

r = 20.34 cm

The radius that can produces such a disk is 20.34 cm

6 0
3 years ago
A rocket is moving with constant velocity of 2000ms and accelerates uniformly at 10ms. What is the velocity after 5 minutes?
AnnyKZ [126]
The velocity is 300ml in 5 mins
8 0
3 years ago
Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:
Deffense [45]

Answer:

a) T=0.01s

b) T=0.001s

c) T=0.00001s

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

T=\frac{1}{f}

Therefore

a)

For

T=100 Hz

T=\frac{1}{100}

T=0.01s

b)

For

F=1kHz

T=\frac{1}{1000}

T=0.001s

c)

For

F=100kHz

T=\frac{1}{100*100}

T=0.00001s

6 0
3 years ago
A. l1 =20 A and l2 =24 A
Masteriza [31]

Answer:

when u find out pls lmk! i have the same question and I've been stuck for a while lol

4 0
2 years ago
A wire loop of radius 0.37 m lies so that an external magnetic field of magnitude 0.35 T is perpendicular to the loop. The field
Galina-37 [17]

Answer:

168.57 mV

Explanation:

Initial magnetic flux = BA , B magnetic field and A is area of loop

= .35 x 3.14 x .37²

= .15 Weber

Final magnetic flux

= - .2 x 3.14 x .37²

= -  .086 Weber

change in flux

.15 +  .086

= .236 Weber

rate of change of flux

= .236 / 1.4

= .16857 V

= 168.57 mV

5 0
3 years ago
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