Question

Consider a glider flying at 400 meters altitude, when suddenly all its static ports become blocked by volcanic ash. The pressure at 400 meters altitude is 96,610 Pascals. The glider then descends to near sea-level and flies at a true airspeed of 25 m/sec.What is the airspeed indicated by the pitot-tube driven airspeed indicator in m/s?

Answer 1

Answer:

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

Explanation:

Pitot tube

$U = \sqrt{\frac{(p_t - p_s)2}{d} }$

U = velocity(m/s)

$p_t$= stagnation pressure (pa)

$p_s$= static pressure (pa)

d = fluid density(kg/m³)

$p_t = p_a_t_m + \frac{1}{2} dv^2$

v = true velocity

= 101325 + 1/2(1.225)(25)²

$p_t = 101,707.8125pa$

$p_s = 96,610pa$

d = 1.225kg/m³

$U = \sqrt{\frac{2(101,707.8125 - 96,610)}{1.225} } \\\\U = 91.23m/s$

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s