Supposing the runner is condensed to a point and moves upward at 2.2 m/s.
It takes a time = 2.2/g = 2.2/9.8 = 0.22 seconds to increase to max height.
Now looking at this condition in opposite - that is the runner is at max height and drops back to earth in 0.22 s (symmetry of this kind of motion).
From what height does any object take 0.22 s to fall to earth (supposing there is no air friction)?
d = 1/2gt²= (0.5)(9.8)(0.22)²= 0.24 m
Answer:
The beam used is a negatively charged electron beam with a velocity of
v = E / B
Explanation:
After reading this long statement we can extract the data to work on the problem.
* They indicate that when the beam passes through the plates it deviates towards the positive plate, so the beam must be negative electrons.
* Now indicates that the electric field and the magnetic field are contracted and that the beam passes without deviating, so the electric and magnetic forces must be balanced

q E = qv B
v = E / B
this configuration is called speed selector
They ask us what type of beam was used.
The beam used is a negatively charged electron beam with a velocity of v = E / B
Answer:

Explanation:
Current is the rate of flow of charge.



As per bernoulli's principle

here
= pressure upwards
= pressure downwards
= velocity of air upwards
= velocity of air downwards
now from this equation we can say that the pressure difference will be

now the force due to this pressure difference will be

so this is the above force which is given above
Answer:
3.48 seconds
Explanation:
At maximum height Vf=0 m/s
Vf= Vi - g*t
⇒g*t= Vi
⇒t= Vi/g
⇒t= 112/32.17 sec
⇒ t= 3.48 s
so the projectile will achieve its maximum height in 3.48 seconds.