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jek_recluse [69]
3 years ago
15

Based on location in the periodic table, which element has chemical properties that are most similar to iodine

Chemistry
2 answers:
patriot [66]3 years ago
5 0

Answer:fluorine

Explanation:

Ymorist [56]3 years ago
3 0

Based on location in the periodic table, fluorine (F) has chemical properties that are most similar to iodine.

In the periodic table, elements are classified in groups and periods. The elements in the same group are chemically similar and they have the same number of valence electrons. Elements in the same period have the same highest energy level.

Hence, when looking for an element that is most chemically similar to iodine, we have to consider the element that is in the same group with iodine.

Both fluorine are iodine are both in group 17 hence, fluorine is most chemically similar to iodine.

Learn more: brainly.com/question/11155928

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Wavelength because it is shorter
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In which way does a balanced chemical equation demonstrate the conservation of matter?​
Alika [10]

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Every chemical equation adheres to the law of every conservation of mass and the states of matter cannot be created or destroyed  

Explanation:

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3 years ago
A mixture of A and B is capable of being ignited only if the mole percent of A is 6 %. A mixture containing 9.0 mole% A in B flo
atroni [7]

Explanation:

As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.

Hence, calculate the molecular weight of the mixture as follows.

             Weight = 0.09 \times 16.04 + 0.91 \times 29

                          = 27.8336 g/mol

And, molar flow rate of air and mixture is calculated as follows.

                    \frac{800}{27.8336}

                     = 28.74 kmol/hr

Now, applying component balance as follows.

                0.09 \times 28.74 + 0 \times F_{B} = 0.06F_{p}

                   F_{p} = 43.11 kmol/hr

                   F_{A} + F_{B} = F_{p}

                          F_{B} = 43.11 - 28.74

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So, mass flow rate of pure (B), is F_{B} = 14.37 \times 29

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According to the product stream, 6 mol% A and 94 mol% B is there.

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Mass of product stream = 1216.67 kg/hr

Hence, mole of O_{2} into the product stream is as follows.

                    0.21 \times 0.94 \times 43.11

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Therefore, calculate the mass % of O_{2} into the stream as follows.

                 \frac{272.31}{1216.67} \times 100

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4 0
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See explanation

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5 0
3 years ago
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