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LiRa [457]
3 years ago
12

Use the accepted values for the molar masses of zinc and gold to determine the mass of gold needed to have the same number of at

oms as 10 g of zinc.
Chemistry
1 answer:
Monica [59]3 years ago
5 0

Answer:

30 g of Au have the same number of atoms as 10 g of Zn

Explanation:

Molar mass Au: 196.97 g/m

Molar mass Zn: 65.41 g/m

10 g of Zn are (mass / molar mass) = 0.153 moles

(10 g / 65.41 g/m)

And now let's count the atoms in this amount of Zn ( mol . NA)

0.153 m . 6.02×10²³ = 9.20×10²² atoms of Zn

In which mass of Au, will we have, these quantity of atoms.

So 9.20×10²² atoms are contained in 0.153 moles.

Then, let's convert the moles in mass (mol . molar mass) to get the answer.

0.153 m . 196.97 g/m = 30.1 g

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Alkenes can be hydrated via the addition of borane to yield alcohols with non-Markovnikov regiochemistry.
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Answer:

The given statement is true.

Explanation:

Initially, the addition of borane to the alkene takes place in the form of a concerted reaction owing to the dissociation of the bond and subsequent formation, which occurs at a similar time. After that the Anti Markovnikov supplementation of boron takes place. The addition of this atom takes place with the less substituted carbon of the alkene that then substitutes the molecule of hydrogen on the more substituted carbon.

Then through the donation of a pair of electrons from the hydrogen peroxide ion, the process of oxidation takes place resulting in the formation of trialkylborane. After this realignment of an R group with its pair of bonding, electrons take place with adjacent oxygen resulting in the withdrawal of a hydroxide ion. Eventually, the trialkylborate reacts with the aqueous NaOH to generate alcohol and sodium borate as the side product.

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Write the balanced NET IONIC equation for the reaction that occurs when perchloric acid and calcium hypochlorite are combined. I
Elanso [62]

Answer:

H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}

Explanation:

Hello there!

In this case, since perchloric acid is HClO4 and is a strong acid and calcium hypochlorite is Ca(ClO)2, the undergoing molecular chemical reaction turns out:

2HClO_4{(aq)}+Ca(ClO)_2{(aq)}\rightarrow 2HClO{(aq)}+Ca(ClO_4)_2{(aq)}

Thus, since the resulting hypochlorous acid is weak, it does not fully ionize, so it remains unionized, however, we can write the ions for the other species:

2H^++2(ClO_4)^-+Ca^{2+}+2(ClO)^-\rightarrow 2HClO{(aq)}+Ca^{2+}+2(ClO_4)^-

Now, we can cancel out the spectator ions, calcium and perchlorate, to obtain:

2H^+(aq)+2(ClO)^-(aq)\rightarrow 2HClO{(aq)}\\\\H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}

Best regards!

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lubasha [3.4K]

Answer:

11. A

12. B

13. D

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